How do you solve $ 6{t^2} = - 4t $

Hint: The equation given in the question is a quadratic equation. We have to find the value of the variable “t”. as the method is not mentioned using the easiest method. Take all the terms to the left-hand side and then “t” as common. And equate the two terms to zero.

Complete step by step solution:
The equation given is the quadratic equation in “t”. There are many ways to solve a quadratic equation. Here the method to solve is not given, so we are free to use any method. We are using the easiest method.
Firstly, take all the terms to the left-hand side while changing the signs, the positive sign would change to negative and vice-versa and add zero to the right-hand side.
 $ 6{t^2} + 4t = 0 $
Now, take the “t” common from the two terms
 $\Rightarrow t(6t + 4) = 0 $
Equate the two terms to zero.
 $\Rightarrow t = 0 $ and $ 6t + 4 = 0 $
Now, divide the six and hence we will find the values of ”t”.
 $\Rightarrow t = - \dfrac{4}{6} $
Required answer of the question is $ t = 0, - \dfrac{2}{3} $
So, the correct answer is “ $ t = 0, - \dfrac{2}{3} $ ”.

Note: Be careful about the signs. Note the equation from the question to our answer sheet carefully. As most students note the wrong statement and hence the whole answer becomes wrong. Do the calculations with full attention and do as much practice as you can.