How do you solve \[6\left( 2x-4 \right)=-20\]?

Hint: We will solve this question using linear equation basic concepts. In our question first we will remove the parentheses by multiplying with 6. Now we will try to make terms come on one side i.e., \[x\]containing terms on one side and remaining on the other side. Now we will perform required arithmetic operations to arrive at the solution.

Complete step-by-step answer:
Given equation is
\[6\left( 2x-4 \right)=-20\]
First we have removed the parenthesis by multiplying with terms inside the parenthesis with 6.
We get
\[\Rightarrow 12x-24=-20\]
Now we have to make the terms come to one side. For this we have to make \[x\] containing terms on one side and constants on the other side.
To do this we have to add \[24\] on both sides of the equation
\[\Rightarrow 12x-24+24=-20+24\]
Now by simplifying we get
\[\Rightarrow 12x=4\]
Now we have to find the value of \[x\]. For this we have to divide with \[12\] on both sides of the equation.
Then we will get
\[\Rightarrow \dfrac{12x}{12}=\dfrac{4}{12}\]
By simplifying the above equation. We get
\[\Rightarrow x=\dfrac{1}{3}\]
So by simplifying the given equation \[6\left( 2x-4 \right)=-20\] we will get the \[x\] value as
\[x=\dfrac{1}{3}\]
We can leave it like this otherwise we can convert it into decimal form where we will get a recursive decimal
\[x=0.33333\].

Note: We can also check the answer by back substituting the \[x\] value in the equation. We can also do it in multiple different ways like first we can divide the equation with 6 and then solving for \[x\]. But the way we had done it was easier when it came to the calculation part.