How do you solve \[4x+7=27\]?
Answer
624k+ views
Hint: In this problem, we have to solve the given equation and find the value of x. We can first subtract the number 7 on both the left-hand side and the right-hand side of the given equation and cancel similar terms on the left-hand side. We can then divide the number 4 on both the left-hand side and the right-hand side to get the value of x.
Complete step by step answer:
We know that the given equation to be solved to find the value of x is,
\[4x+7=27\]
We can first subtract the number 7 on both left-hand side and the right-hand side of the given equation and cancel similar terms on the left-hand side, we get
\[\begin{align}
& \Rightarrow 4x+7-7=27-7 \\
& \Rightarrow 4x=20 \\
\end{align}\]
We can now divide the number 4 on both the left-hand side and the right-hand side to get the value of x.
\[\Rightarrow \dfrac{4x}{4}=\dfrac{20}{4}\]
We can now cancel the similar terms on the left-hand side and use multiplication tables to can the terms on the right-hand side, we get
\[\Rightarrow x=5\]
Therefore, the value of x = 5.
Note: We can also check this value by substituting the resulted value in the given equation, we get
\[\begin{align}
& \Rightarrow 4\left( 5 \right)+7=27 \\
& \Rightarrow 20+7=27 \\
\end{align}\]
We can see that we got the same number on both the left-hand side and the right-hand side. Therefore, it is a correct value. Students make mistakes while using multiplication to simplify, we should know multiplication tables to solve these types of problems.
Complete step by step answer:
We know that the given equation to be solved to find the value of x is,
\[4x+7=27\]
We can first subtract the number 7 on both left-hand side and the right-hand side of the given equation and cancel similar terms on the left-hand side, we get
\[\begin{align}
& \Rightarrow 4x+7-7=27-7 \\
& \Rightarrow 4x=20 \\
\end{align}\]
We can now divide the number 4 on both the left-hand side and the right-hand side to get the value of x.
\[\Rightarrow \dfrac{4x}{4}=\dfrac{20}{4}\]
We can now cancel the similar terms on the left-hand side and use multiplication tables to can the terms on the right-hand side, we get
\[\Rightarrow x=5\]
Therefore, the value of x = 5.
Note: We can also check this value by substituting the resulted value in the given equation, we get
\[\begin{align}
& \Rightarrow 4\left( 5 \right)+7=27 \\
& \Rightarrow 20+7=27 \\
\end{align}\]
We can see that we got the same number on both the left-hand side and the right-hand side. Therefore, it is a correct value. Students make mistakes while using multiplication to simplify, we should know multiplication tables to solve these types of problems.
Recently Updated Pages
Explain the Treaty of Vienna of 1815 class 10 social science CBSE

10 examples of friction in our daily life

Draw a diagram of nephron and explain its structur class 11 biology CBSE

Write structures of the following compounds i 2 Chloro3methylpentane class 11 chemistry CBSE

A Paragraph on Pollution in about 100-150 Words

XIX+XXX A 49 B 51 C 55 D 44 class 5 maths CBSE

Trending doubts
What is BLO What is the full form of BLO class 8 social science CBSE

Citizens of India can vote at the age of A 18 years class 8 social science CBSE

Full form of STD, ISD and PCO

Write an article on Global warming in about 200 words

What are the methods of reducing friction. Explain

Write a letter to the Municipal Commissioner to inform class 8 english CBSE


