How do you solve \[41=12d-7\]?

Hint: From the question given, we have been asked to solve \[41=12d-7\]. The given question can be solved by using some simple transformations to the equation given. Certain transformations have to be made for the given equation to get the solution for the given question. For this question, we have to move the constant in the left hand side of the given equation to the right hand side of the given equation. Then, on further simplifying the equation, we can get the final solution for the given equation from the question given.

Complete step by step answer:
From the question given, it has been given that \[41=12d-7\]
As we have been already discussed above, we have to the move the constant in the left hand side of the equation to the right hand side of the equation.
Therefore, we have to move \[41\] from the left hand side of the equation to the right hand side of the equation.
By shifting \[41\] from left hand side of the equation to the right hand side of the equation, we get the below equation,
\[41=12d-7\]
\[\Rightarrow 12d-7-41=0\]
On furthermore simplification of the above equation, we get
\[\Rightarrow 12d-48=0\]
Now, shift \[-48\] from the left hand side of the equation to the right hand side of the equation. Then, we get \[\Rightarrow 12d=48\]
Now, shift \[12\] from the left hand side of the equation to the right hand side of the equation. Then, we get
\[\Rightarrow d=\dfrac{48}{12}\]
\[\Rightarrow d=4\]
Therefore, as we have been discussed earlier, the given question has been solved by using a simple transformation to the given question.

Note:
We should know to use the transformations well and perfect. Certain transformations have to be made for the given question, so that it will become easier to simplify further more. Also, we should not get confused while doing the transformations. Also, we should be very careful while doing the calculation. Similarly we can solve \[40=10x-5\] as follows $10x=45\Rightarrow x=4.5$