How do you solve $ 3x-8=22 $ ?

Hint: In this question, we are given an equation in terms of x and we need to solve it to find the value of x which satisfies the equation. For this, we will add, subtract, multiply and divide some numbers into both sides of the equation such that we are left with the variable x on the left side of the equation and a constant on the right side of the equation. The value of the constant will be the required value of x which satisfies the equation.

Complete step by step answer:
Here we are given the equation in terms of x as $ 3x-8=22 $.
We need to find the value of x which satisfies this equation. For this let us add, subtract, multiply and divide some numbers into both sides of the equation such that we are left with an equation of the form x = c where c is the constant.
We have $ 3x-8=22 $ .
As there is a constant 8 on the left side of the equation which is not required. So let us remove it. Adding 8 on both sides of the equation we get $ 3x-8+8=22+8 $ .
8 subtracted from 8 gives 0 whereas 22 added to 8 gives us 30 so our equation reduces to $ 3x=30 $.
Now we can see that equation is not of the form x = c as there is a coefficient 3 with variable x. So let us remove it. For this let us divide both sides by 3 we get $ \dfrac{3x}{3}=30 $ .
On the left side of the equation, 3 divided by 3 gives us 1 whereas on the right side of the equation 30 divided by 3 gives us 10 so, we are left with x = 10 which is of the form x = c. Hence the value of x is 10 which satisfies the given equation.

Note:
Students should take care of the signs while adding, subtracting terms on both sides of the equation. Students can also check their answers by putting back the value of x in original equation i.e. putting x = 10 in $ 3x-8=22 $ we get, $ 3\left( 10 \right)-8=22 $ .
3 multiplied by 10 gives 30 so we get 30-8 = 22.
8 subtracted from 30 gives us 22 so we get 22 = 22.
Left side is equal to the right side. Therefore, the value of x as 10 is the correct answer.