How do you solve $2y+5=19$ ?

Hint: In the equation we have $2y+5=19$. In the given expression we can observe the two arithmetic operations: first one is multiplication and second one is addition. To solve the equation, we need to apply the reverse operation for the given operations. The first operation is addition, so we will perform the subtraction operation on both sides of the expression and after we will do division operation for multiplication operation. Now we will get our required result.

Complete step by step answer:
Given that,$2y+5=19$ .
In the above expression we have the digit $5$ in addition on the left side. To solve the expression, we need to subtract the same $5$ on both sides. Then we will get
$2y+5-5=19-5$
We know that $+x-x=0$ ,then we will have
$2y=14$
In the above simplified expression, we can observe that $2$ is multiplying $y$ on LHS. To solve the above expression, we will divide the same $2$ on both sides. Then we will have
$\dfrac{2y}{2}=\dfrac{14}{2}$
We know that $\dfrac{x}{x}=1$, then we will get
$y=7$

Note:
We can check whether the obtained result is right or wrong by plugging in any value in the given expression and checking the result.
We got $y=7$, so we will substitute $7$ in the place of $y$ in the given equation, Then we will get
$\begin{align}
  & 2y+5=19 \\
 & \Rightarrow 2\left( 7 \right)+5=19 \\
\end{align}$
We have the value $2\left( 7 \right)=14$, substituting this value in the above equation, then we will have
$\Rightarrow 14+5=19$
Adding $5$ to $14$, we will get $19$ as result, then we will get
$\therefore 19=19$
In the above equation we can say that $L.H.S=R.H.S$.
Hence the obtained result is correct.