How do you solve $25-4x+6x+15$ .

Hint: To solve $25-4x+6x+15$ , we have to combine the like terms. Then we will add each set of like terms since like terms can only be added and subtracted. We can either leave the answer as it is or take the common factor outside.

Complete step-by-step solution:
We have to solve $25-4x+6x+15$ . For this we have to combine the like terms.
$\Rightarrow \left( 25+15 \right)+\left( -4x+6x \right)$
Now, let us add the first set of like terms.
\[\Rightarrow 40+\left( -4x+6x \right)\]
Let us add the terms containing x, that is, we have to add the coefficients of x.
\[\Rightarrow 40+2x\]
We can either leave the answer as it is or take the common factor outside. Here, we can see that 2 is a common factor.
\[\Rightarrow 2\left( 20+x \right)\]
Hence, the answer is \[40+2x\] or \[2\left( 20+x \right)\] .

Note: Students must know basic number laws to solve these types of problems. They must know what the terms are. Like terms are the terms with same variables along with same exponents. Constant terms are also like terms. We cannot solve the given expression since the expression is not equated to some value. We can also simplify the given expression as follows.
We have first combined the terms in x.
$25+\left( -4x+6x \right)+15$
Let us add the terms in x.
$\Rightarrow 25+2x+15$
We have to use commutative property to group the constants.
We know that $a+b=b+c$ . Hence we can write the above equation as
$\Rightarrow 25+15+2x$
Let us add the constant terms. We will get
$\Rightarrow 40+2x$