How do you simplify ${{i}^{59}}$?
Answer
618.3k+ views
Hint: To solve this question, we need to make the exponent on $i$ equal to a multiple of four. Since the exponent is equal to $59$ which is one less than $60$, a multiple of four, we need to multiply and divide the given expression by $i$ to obtain $\dfrac{{{i}^{60}}}{i}$. Then, we have to use the relation ${{i}^{4}}=1$ to show that any multiple of four, raised to $i$ given one. Using this our expression will get reduced to $\dfrac{1}{i}$. Finally, on dividing and multiplying the obtained expression by $i$ we will get the simplified expression.
Complete step by step solution:
Let us write the expression given in the above question in the below equation as
$\Rightarrow E={{i}^{59}}........\left( i \right)$
Now, we know that $i$ is equal to the square root one minus one, which in turn means that the square of $i$ is equal to minus one, that is,
\[\Rightarrow {{i}^{2}}=-1.......\left( ii \right)\]
Squaring both the sides, we get
$\begin{align}
& \Rightarrow {{\left( {{i}^{2}} \right)}^{2}}={{\left( -1 \right)}^{2}} \\
& \Rightarrow {{i}^{4}}=1 \\
\end{align}$
Raising the terms on both sides of the above equation to the exponent of $n$, where $n$ is a natural number, we get
$\begin{align}
& \Rightarrow {{\left( {{i}^{4}} \right)}^{n}}={{\left( 1 \right)}^{n}} \\
& \Rightarrow {{i}^{4n}}=1 \\
\end{align}$
From the above equation, we can say that the value of $i$ raised to a multiple of four is equal to one.
Now, we consider the equation (i)
$\Rightarrow E={{i}^{59}}$
Multiplying and dividing by $i$ we get
$\begin{align}
& \Rightarrow E={{i}^{59}}\times \dfrac{i}{i} \\
& \Rightarrow E=\dfrac{{{i}^{60}}}{i} \\
\end{align}$
Since $60$ is a multiple of four, we can substitute ${{i}^{60}}=1$ in the above equation to get
$\Rightarrow E=\dfrac{1}{i}$
Multiplying and dividing by $i$ we get
\[\Rightarrow E=\dfrac{i}{{{i}^{2}}}\]
Finally, substituting (ii) in the above equation, we get
$\begin{align}
& \Rightarrow E=\dfrac{i}{-1} \\
& \Rightarrow E=-i \\
\end{align}$
Hence, the given expression is simplified as $-i$.
Note: The equation ${{i}^{4n}}=1$, which we obtained in the above solution is an identity. We must remember it in order to quickly solve these kinds of problems. Also, we must remember the identities \[{{i}^{2}}=-1\] and $\dfrac{1}{i}=-i$ must be remembered for solving these types of questions.
Complete step by step solution:
Let us write the expression given in the above question in the below equation as
$\Rightarrow E={{i}^{59}}........\left( i \right)$
Now, we know that $i$ is equal to the square root one minus one, which in turn means that the square of $i$ is equal to minus one, that is,
\[\Rightarrow {{i}^{2}}=-1.......\left( ii \right)\]
Squaring both the sides, we get
$\begin{align}
& \Rightarrow {{\left( {{i}^{2}} \right)}^{2}}={{\left( -1 \right)}^{2}} \\
& \Rightarrow {{i}^{4}}=1 \\
\end{align}$
Raising the terms on both sides of the above equation to the exponent of $n$, where $n$ is a natural number, we get
$\begin{align}
& \Rightarrow {{\left( {{i}^{4}} \right)}^{n}}={{\left( 1 \right)}^{n}} \\
& \Rightarrow {{i}^{4n}}=1 \\
\end{align}$
From the above equation, we can say that the value of $i$ raised to a multiple of four is equal to one.
Now, we consider the equation (i)
$\Rightarrow E={{i}^{59}}$
Multiplying and dividing by $i$ we get
$\begin{align}
& \Rightarrow E={{i}^{59}}\times \dfrac{i}{i} \\
& \Rightarrow E=\dfrac{{{i}^{60}}}{i} \\
\end{align}$
Since $60$ is a multiple of four, we can substitute ${{i}^{60}}=1$ in the above equation to get
$\Rightarrow E=\dfrac{1}{i}$
Multiplying and dividing by $i$ we get
\[\Rightarrow E=\dfrac{i}{{{i}^{2}}}\]
Finally, substituting (ii) in the above equation, we get
$\begin{align}
& \Rightarrow E=\dfrac{i}{-1} \\
& \Rightarrow E=-i \\
\end{align}$
Hence, the given expression is simplified as $-i$.
Note: The equation ${{i}^{4n}}=1$, which we obtained in the above solution is an identity. We must remember it in order to quickly solve these kinds of problems. Also, we must remember the identities \[{{i}^{2}}=-1\] and $\dfrac{1}{i}=-i$ must be remembered for solving these types of questions.
Recently Updated Pages
10 examples of friction in our daily life

Draw a diagram of nephron and explain its structur class 11 biology CBSE

Write structures of the following compounds i 2 Chloro3methylpentane class 11 chemistry CBSE

What is BLO What is the full form of BLO class 8 social science CBSE

Explain the Treaty of Vienna of 1815 class 10 social science CBSE

A Paragraph on Pollution in about 100-150 Words

Trending doubts
Find the value of the expression given below sin 30circ class 11 maths CBSE

What do you mean by retardation What is its SI uni class 11 physics CBSE

Difference between physical and chemical change class 11 chemistry CBSE

What are derived physical quantities Give any two examples class 11 physics CBSE

Which of the following is a derived physical quantity class 11 physics CBSE

Describe various types of epithelial tissues with the class 11 biology CBSE

