How do you simplify $9-3(2x-4)$?

Hint: We are given an equation as $9-3(2x-4)$. We are asked to simplify, as we can see it has brackets, so to simplify we will learn about BODMAS, then we will learn about addition or subtraction between the like terms. We will open brackets and multiply terms by one another.

Complete step by step solution:
We are given $9-3(2x-4)$, we have to simplify it, as we can see that it has a bracket so we need to use BODMAS, BODMAS in a rearrangement which tells us which tool need to be operated when, in this as name stand.
B- Bracket
o- of
D-division
M-multiplication
A-addition
S-Subtraction
We will perform the tool in the given order since our problem $9-3(2x-4)$ has a bracket, So we try to solve the term inside it. We have $3x$ and $y$ they both are not like terms, like terms are those which are of the same kind. Since they are not like terms, so there is nothing to solve in the brackets.
So we open it up. When we open we multiply $3$ with the bracket.
$\Rightarrow 9-(2x-4)=9-3(2x)-3(-4)$
Now we multiply $-3\,\,and\,\,2x$
We get $-6x$
And we multiply $(-3)\,and\,(-4)$we get $12$
=9-6x+12So, $9-3(2x-4)=9-6x+12$
Now we have no brackets, so we need to add or subtract as needed.
We will add like terms.
As $90$ and $12$ are like (being both constant). So we add them. $a+12=21$. So we get,
$\Rightarrow 21-6x$
Now as $21$ and $6x$ are not like terms, so they cannot be subtracted further. Hence, we get $9-3(2x-4)=21-6x$

Note: We need to be careful that we do not end up adding or subtracting unlike terms like $21ax=6x$ or $4-2x=2x$. Also, we need to know that product of $2$
 Negative and positive is always negative also we can never have the sequence of BODMAS. If we do that, we will not get the correct solution.