How do you graph $y = \dfrac{1}{{1 + {x^2}}}$ ?
Answer
624.3k+ views
Hint: In this question, we are given an equation containing two variable unknown quantities. To plot a given equation of graph, we must know the coordinates of at least two points that lie on the curve. To find those two points we put some random values of x and get the values of y from the equation. Plotting the two obtained points and extending the line, we get the required graph.
Complete step-by-step solution:
The given function is
\[y = \dfrac{1}{{1 + {x^2}}}\]
As the numerator is equal to 1 so it is positive and the denominator is the square of a number added to 1, so the denominator is also positive. Thus the value of y for any value of x comes out to be positive and x can take any real number as its value.
As the value of the denominator decreases, the value of y will increase, so the value of y is maximum when x=0.
As the value of x increases or decreases, the square of x will increase either way and thus the value of the $1 + {x^2}$ increases and value of $y = \dfrac{1}{{1 + {x^2}}}$ decreases.
Hence, the graph of the function $y = \dfrac{1}{{1 + {x^2}}}$is given as –
Note: We see that in this equation the left side contains only ”y” and the right side contains the ratio of 1 and $1 + {x^2}$ , that is, in this equation y is expressed in terms of x, thus the given equation is a function in terms of x. As the value of x changes the value of y also changes. So, x is called the independent variable and y is called the dependent variable.
Complete step-by-step solution:
The given function is
\[y = \dfrac{1}{{1 + {x^2}}}\]
As the numerator is equal to 1 so it is positive and the denominator is the square of a number added to 1, so the denominator is also positive. Thus the value of y for any value of x comes out to be positive and x can take any real number as its value.
As the value of the denominator decreases, the value of y will increase, so the value of y is maximum when x=0.
As the value of x increases or decreases, the square of x will increase either way and thus the value of the $1 + {x^2}$ increases and value of $y = \dfrac{1}{{1 + {x^2}}}$ decreases.
Hence, the graph of the function $y = \dfrac{1}{{1 + {x^2}}}$is given as –
Note: We see that in this equation the left side contains only ”y” and the right side contains the ratio of 1 and $1 + {x^2}$ , that is, in this equation y is expressed in terms of x, thus the given equation is a function in terms of x. As the value of x changes the value of y also changes. So, x is called the independent variable and y is called the dependent variable.
Recently Updated Pages
Write structures of the following compounds i 2 Chloro3methylpentane class 11 chemistry CBSE

What is BLO What is the full form of BLO class 8 social science CBSE

Explain the Treaty of Vienna of 1815 class 10 social science CBSE

A Paragraph on Pollution in about 100-150 Words

XIX+XXX A 49 B 51 C 55 D 44 class 5 maths CBSE

If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

What do you mean by retardation What is its SI uni class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Difference between physical and chemical change class 11 chemistry CBSE

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

