How do you graph $y = - 1$?

Hint: We know the general equation of a straight line is $y = mx + c$ where $m$ is the gradient and $y = c$ is the value where the line cuts the $y - $axis. We know about the cartesian coordinates of points which is $(x,y)$ where $x$ is the abscissa and $y$ is the ordinate.

Complete step by step Solution:
Given that – line equation is $y = - 1$
If we write it in form of our general equation $y = mx + c$ then we will get
$y = 0 + ( - 1)$
Here we can see that we don’t have the gradient which is in our equation of line $y = mx + c$ where $m = 0$ and the value of abscissa $x = 0$
So here we will get $x = 0$ and $y = - 1$
So, we will get our point for drawing a line is the $(0, - 1)$
We got one point for representing line of given linear equation $y = - 1$ on the graph
Now we will put our point on the graph which we got above now our graph for our line is the

The above graph is the required graph for the given line $y = - 1$

Note: We know that general equation of line is $y = mx + c$ we can solve above given equation $y = - 1$ also by comparing it with $y = mx + c$ then we will get $m = 0$ then this means that the slope of given line is the state and it is parallel to the $x - axis$.