How do you graph $y+4x=1$ ?

Hint: Now considering from the question we have been asked to draw the graph of the given straight line equation $y+4x=1$ . From the basic concepts of straight lines we know that the general slope-intercept form of a straight line is given as $y=mx+c$ where $m$ is the slope and $c$ is the $y$ intercept.

Complete step by step solution:
Now considering from the question we have been asked to draw the graph of the given straight line equation $y+4x=1$ .
From the basic concepts of straight lines we know that the general slope-intercept form of a straight line is given as $y=mx+c$ where $m$ is the slope and $c$ is the $y$ intercept.
Hence the $x$ intercept will be given as $\dfrac{-c}{m}$ .
Now for the given expression $y+4x=1\Rightarrow y=-4x+1$ . The slope will be $-4$ , $x$ intercept will be $\dfrac{1}{4}=0.25$ and $y$ intercept will be $1$ .
Hence the given straight line will pass through $\left( 0,1 \right)$ and $\left( 0.25,0 \right)$ .
The graph of the given straight line equation will be as shown below:


Note: While drawing the graph of the given expression we should mark the points accurately and join them exactly in order to obtain an appropriate graph. Similarly the other form of a straight line is given as $ax+by+c=0$ where slope is given as $\dfrac{-a}{b}$ , $x$ intercept is given as $\dfrac{-c}{b}$ and $y$ intercept is given as $\dfrac{-c}{a}$ . If we consider for this expression $y+4x=1\Rightarrow y+4x-1=0$ , then the values of $a,b,c$ will be $4,1,-1$ respectively. Then slope, $x$ and $y$ intercepts will be $-4,0.25,1$ respectively.