How do you find $\theta$ ?
Answer
610.8k+ views
Hint: The value of $\theta $ can be found by using sine and cosine functions. We start to solve the problem by finding the trigonometric functions $\sin \theta $ and $\cos \theta $ for the triangle. To get the value of $\theta $ , we multiply the trigonometric functions with their inverse functions.
Complete step-by-step solution:
The value of $\theta $ can be found out in 2 ways. We can easily find the value of $\theta $ with the use of two trigonometric functions $\sin \theta $ and $\cos \theta $
Case 1:
Firstly, The value of $\theta $ with help of sine function.
Sine is the trigonometric function of any specified angle that is used in the context of a right angle.
It is usually defined as the ratio of the length of the side opposite to an angle to the length of the hypotenuse of the right-angle triangle.
$\sin \theta $= length of the side opposite to angle $\theta $ is divided by the length of the hypotenuse.
In the diagram given in the question,
The length of the side opposite to the angle $\theta $ is b.
The length of the hypotenuse is c.
Therefore, upon substituting we get,
$\Rightarrow \sin \theta =\dfrac{b}{c}$
Now, we must find the value of theta.
Multiplying the above equation with the inverse sine function, we get,
$\Rightarrow arcsin\left( \sin \theta \right)=arcsin\left( \dfrac{b}{c} \right)$
We know that $arcsin\left( \sin \theta \right)=\theta$
Substituting the same,
We get $\theta =\text{ }arcsin\left( \dfrac{b}{c} \right)$
Hence, the value of $\theta$ in terms of arcsine function is given by $\theta =\text{ }arcsin\left( \dfrac{b}{c} \right)$
Case 2:
Secondly, The value of $\theta$ with the help of cosine function.
Cos is the trigonometric function of any specified angle that is used in the context of a right angle.
It is usually defined as the ratio of the length of the side adjacent to an angle to the length of the hypotenuse of the right-angle triangle.
$\cos \theta$ = length of the side adjacent to angle $\theta$ is divided by the length of the hypotenuse.
In the diagram given in the question,
The length of the side adjacent to the angle $\theta$ is a.
The length of the hypotenuse is c.
$\cos \theta =\dfrac{a}{c}$
Now, we must find the value of theta.
Multiplying the above equation with the inverse cosine function, we get,
$\Rightarrow \arccos \left( \cos \theta \right)=\arccos \left( \dfrac{a}{c} \right)$
We know that $\arccos \left( \cos \theta \right)=\theta$
Substituting the same,
We get $\theta =\text{ }\arccos \left( \dfrac{a}{c} \right)$
Hence, the value of $\theta$ in terms of arcsine function is given by $\theta =\text{ }\arccos \left( \dfrac{a}{c} \right)$
Note: The inverse functions in trigonometry are also known as arc functions or anti trigonometric functions. They are majorly known as arc functions because they are most used to find the length of the arc needed to get the given or specified value. We can convert a function into an inverse function and vice versa.
Complete step-by-step solution:
The value of $\theta $ can be found out in 2 ways. We can easily find the value of $\theta $ with the use of two trigonometric functions $\sin \theta $ and $\cos \theta $
Case 1:
Firstly, The value of $\theta $ with help of sine function.
Sine is the trigonometric function of any specified angle that is used in the context of a right angle.
It is usually defined as the ratio of the length of the side opposite to an angle to the length of the hypotenuse of the right-angle triangle.
$\sin \theta $= length of the side opposite to angle $\theta $ is divided by the length of the hypotenuse.
In the diagram given in the question,
The length of the side opposite to the angle $\theta $ is b.
The length of the hypotenuse is c.
Therefore, upon substituting we get,
$\Rightarrow \sin \theta =\dfrac{b}{c}$
Now, we must find the value of theta.
Multiplying the above equation with the inverse sine function, we get,
$\Rightarrow arcsin\left( \sin \theta \right)=arcsin\left( \dfrac{b}{c} \right)$
We know that $arcsin\left( \sin \theta \right)=\theta$
Substituting the same,
We get $\theta =\text{ }arcsin\left( \dfrac{b}{c} \right)$
Hence, the value of $\theta$ in terms of arcsine function is given by $\theta =\text{ }arcsin\left( \dfrac{b}{c} \right)$
Case 2:
Secondly, The value of $\theta$ with the help of cosine function.
Cos is the trigonometric function of any specified angle that is used in the context of a right angle.
It is usually defined as the ratio of the length of the side adjacent to an angle to the length of the hypotenuse of the right-angle triangle.
$\cos \theta$ = length of the side adjacent to angle $\theta$ is divided by the length of the hypotenuse.
In the diagram given in the question,
The length of the side adjacent to the angle $\theta$ is a.
The length of the hypotenuse is c.
$\cos \theta =\dfrac{a}{c}$
Now, we must find the value of theta.
Multiplying the above equation with the inverse cosine function, we get,
$\Rightarrow \arccos \left( \cos \theta \right)=\arccos \left( \dfrac{a}{c} \right)$
We know that $\arccos \left( \cos \theta \right)=\theta$
Substituting the same,
We get $\theta =\text{ }\arccos \left( \dfrac{a}{c} \right)$
Hence, the value of $\theta$ in terms of arcsine function is given by $\theta =\text{ }\arccos \left( \dfrac{a}{c} \right)$
Note: The inverse functions in trigonometry are also known as arc functions or anti trigonometric functions. They are majorly known as arc functions because they are most used to find the length of the arc needed to get the given or specified value. We can convert a function into an inverse function and vice versa.
Recently Updated Pages
Write structures of the following compounds i 2 Chloro3methylpentane class 11 chemistry CBSE

What is BLO What is the full form of BLO class 8 social science CBSE

Explain the Treaty of Vienna of 1815 class 10 social science CBSE

A Paragraph on Pollution in about 100-150 Words

XIX+XXX A 49 B 51 C 55 D 44 class 5 maths CBSE

If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

What do you mean by retardation What is its SI uni class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Difference between physical and chemical change class 11 chemistry CBSE

