Give possible expressions for the length and breadth of the rectangle whose area is: \[4{{a}^{2}}+\text{ }4a - 3\] .
A) (2a – 3) (2a + 2)
B) (2a – 1) (2a – 3)
C) (2a + 3) (2a – 1)
D) None of the above
Answer
682.2k+ views
Hint: Let us first learn about Rectangle and its Area.
RECTANGLE: A parallelogram all of whose angles are right angles, especially the one with adjacent sides of unequal length is called a rectangle.
AREA OF RECTANGLE: The formula that is used to calculate the area of a rectangle is \[L\times B\], where ‘L’ stands for the Length of the Rectangle and ‘B’ stands for Breadth of the Rectangle.
Complete step-by-step answer:
Let us now solve this question.
A) (2a– 3) (2a + 2). As we know that this is the length and breadth of the rectangle, and the formula to calculate the area of the rectangle, therefore, we will multiply (2a– 3) and (2a + 2) and check whether their product is equal to \[4{{a}^{2}}+\text{ }4a - 3\] or not.
(2a– 3) (2a + 2) = 2a (2a + 2) – 3 (2a + 2) = \[4{{a}^{2}}+\text{ }4a\text{ }\text{ }-6a\text{ }\text{ }-6\text{ }=\text{ }4{{a}^{2}}\text{ }-2a\text{ }\text{ }-6\]
We can observe that \[4{{a}^{2}}\text{ }-2a\text{ }\text{ }-6\ne 4{{a}^{2}}+\text{ }4a\text{ }\text{ }-3\] .
Therefore, this is not a correct option.
B) (2a – 1) (2a – 3). We will multiply (2a– 1) and (2a – 3) and check whether their product is equal to \[4{{a}^{2}}+\text{ }4a - 3\] or not.
(2a – 1) (2a – 3) = 2a (2a – 3) – 1 (2a – 3) = \[4{{a}^{2}}\text{ }-6a\text{ }\text{ }-2a\text{ }+\text{ }3\text{ }=\text{ }4{{a}^{2}}\text{ }-8a\text{ }+\text{ }3\] .
We can observe that \[4{{a}^{2}}\text{ }-8a\text{ }+\text{ }3\ne 4{{a}^{2}}+\text{ }4a\text{ }\text{ }-3\] .
Therefore, this is not a correct option.
C) (2a + 3) (2a – 1). We will multiply (2a + 3) and (2a – 1) and check whether their product is equal to \[4{{a}^{2}}+\text{ }4a - 3\] or not.
(2a + 3) (2a – 1) = 2a (2a – 1) + 3 (2a – 1) = \[4{{a}^{2}}\text{ }-2a\text{ }+\text{ }6a\text{ }\text{ }-3\text{ }=\text{ }4{{a}^{2}}+\text{ }4a\text{ }\text{ }-3\] .
We can observe that \[4{{a}^{2}}+\text{ }4a\text{ }\text{ }-3=4{{a}^{2}}+\text{ }4a\text{ }\text{ }-3\]. Therefore, this is the correct option.
D) None of the above. This cannot be the correct option as the correct option is (C).
After solving this question, the answer of this question is (C) (2a + 3) (2a – 1).
Note: One must do all the calculation very carefully in this question. Any mistake in the calculations can make the answer wrong.
RECTANGLE: A parallelogram all of whose angles are right angles, especially the one with adjacent sides of unequal length is called a rectangle.
AREA OF RECTANGLE: The formula that is used to calculate the area of a rectangle is \[L\times B\], where ‘L’ stands for the Length of the Rectangle and ‘B’ stands for Breadth of the Rectangle.
Complete step-by-step answer:
Let us now solve this question.
A) (2a– 3) (2a + 2). As we know that this is the length and breadth of the rectangle, and the formula to calculate the area of the rectangle, therefore, we will multiply (2a– 3) and (2a + 2) and check whether their product is equal to \[4{{a}^{2}}+\text{ }4a - 3\] or not.
(2a– 3) (2a + 2) = 2a (2a + 2) – 3 (2a + 2) = \[4{{a}^{2}}+\text{ }4a\text{ }\text{ }-6a\text{ }\text{ }-6\text{ }=\text{ }4{{a}^{2}}\text{ }-2a\text{ }\text{ }-6\]
We can observe that \[4{{a}^{2}}\text{ }-2a\text{ }\text{ }-6\ne 4{{a}^{2}}+\text{ }4a\text{ }\text{ }-3\] .
Therefore, this is not a correct option.
B) (2a – 1) (2a – 3). We will multiply (2a– 1) and (2a – 3) and check whether their product is equal to \[4{{a}^{2}}+\text{ }4a - 3\] or not.
(2a – 1) (2a – 3) = 2a (2a – 3) – 1 (2a – 3) = \[4{{a}^{2}}\text{ }-6a\text{ }\text{ }-2a\text{ }+\text{ }3\text{ }=\text{ }4{{a}^{2}}\text{ }-8a\text{ }+\text{ }3\] .
We can observe that \[4{{a}^{2}}\text{ }-8a\text{ }+\text{ }3\ne 4{{a}^{2}}+\text{ }4a\text{ }\text{ }-3\] .
Therefore, this is not a correct option.
C) (2a + 3) (2a – 1). We will multiply (2a + 3) and (2a – 1) and check whether their product is equal to \[4{{a}^{2}}+\text{ }4a - 3\] or not.
(2a + 3) (2a – 1) = 2a (2a – 1) + 3 (2a – 1) = \[4{{a}^{2}}\text{ }-2a\text{ }+\text{ }6a\text{ }\text{ }-3\text{ }=\text{ }4{{a}^{2}}+\text{ }4a\text{ }\text{ }-3\] .
We can observe that \[4{{a}^{2}}+\text{ }4a\text{ }\text{ }-3=4{{a}^{2}}+\text{ }4a\text{ }\text{ }-3\]. Therefore, this is the correct option.
D) None of the above. This cannot be the correct option as the correct option is (C).
After solving this question, the answer of this question is (C) (2a + 3) (2a – 1).
Note: One must do all the calculation very carefully in this question. Any mistake in the calculations can make the answer wrong.
Recently Updated Pages
Find the greatest six digit number that is exactly class 8 maths CBSE

What is the time difference between India and Cana class 8 social science CBSE

Compare LPG and wood as fuels class 8 chemistry CBSE

In Indian rupees 1 trillion is equal to how many c class 8 maths CBSE

30 opposite words in English from a to z class 8 english CBSE

How many cubic feet equals to 1 unit sand class 8 maths CBSE

Trending doubts
One cusec is equal to how many liters class 8 maths CBSE

Who commanded the Hector the first British trading class 8 social science CBSE

What is the feminine gender of a stag class 8 english CBSE

Advantages and disadvantages of science

Write a letter to the Municipal Commissioner to inform class 8 english CBSE

Which district has the lowest sex ratio in Karnataka class 8 social science CBSE


