First, second and third IP values are 100eV, 150eV, and 1500 eV. The element can be:
A. Be
B. B
C. F
D. Na

Hint: The elements present in group 2 and group 15 have completely filled or partially filled electronic configuration, therefore it requires a large amount of energy to remove an electron from the orbital with completely filled electrons.

Complete answer:
-Ionization energy is defined as the measure of the struggle in separating the electrons from the atom or ion. It is also defined as the amount of energy that a gaseous atom present in the ground state absorbs to release an electron to form a cation.
$H(g) \to {H^ + }(g) + {e^ - }$
-The energy applied is expressed in terms of kJ/mol.
$M\xrightarrow[{100}]{{I{E_1}}}{M^ + }\xrightarrow[{150}]{{I{E_2}}}{M^{2 + }}\xrightarrow[{1500}]{{I{E_3}}}{M^{3 + }}$
-The ionization energy for converting M to ${M^ + }$ is 100.
-The ionization energy for converting ${M^ + }$ to ${M^{2 + }}$ is 150.
-The ionization energy for converting ${M^{2 + }}$ to ${M^{3 + }}$ is 1500.
-As we can see that the ionization energy is very high during the conversion of ${M^{2 + }}$ to ${M^{3 + }}$. It means that the ion or atom has reached the stability. The atom must be a noble gas element or Group 2 element which contains completely filled or half-filled electrons in the valence shell.
-As, the ionization energy is very high to remove the electrons from the half-filled or completely filled electronic configuration.
-From the given element, beryllium is the alkaline earth metal which contains half-filled electrons in its valence shell.