Find the hyperbola whose asymptotes are given $2x - y = 3$, $3x + y = 7$ and which passes through the point $\left( {1,1} \right)$.
Answer
654.9k+ views
Hint: In the given question, we have to find out the equation of hyperbola and information of asymptote its equation is given as well as hyperbola passes through is $\left( {1,1} \right)$ also given. To work it out, use the relation (product of asymptote $ + $constant $ = 0$) as it is also an equation of hyperbola. Since, $\left( {1,1} \right)$ is a points from where it passes put $\left( {x,y} \right) = \left( {1,1} \right)$ in the said equation & find value of $k$. Then put the value of $k$ in the equation & work out the equation of hyperbola.
Complete step-by-step answer:
We know that –
Equation of hyperbola differs from the joint equation of its asymptotes by a constant.
Equation of hyperbola –
$ \Rightarrow $(product of asymptote) $ + $constant$\left( k \right)$$ \Rightarrow $$0$
Given –
Asymptote equations are –
${
2x - y = 3 \\
\Rightarrow 2x - y - 3 = 0 \\
\therefore \left( {2x - y - 3} \right)\left( {3x + y - 7} \right) + k = 0..........(i) \\
} $
And,
${
3x + y = 7 \\
\Rightarrow 3x + y - 7 = 0 \\
} $
Now, it is given that hyperbola passes through $\left( {1,1} \right)$
$\therefore $Putting $\left( {x.y} \right) = \left( {1,1} \right)$ in equation $(i)$
${
\Rightarrow (2 - 1 - 3)(3 + 1 - 7) + k = 0 \\
\Rightarrow ( - 2 \times - 3) + k = 0 \\
\Rightarrow k = - 6 \\
} $
$\therefore $Putting $k = - 6$ in require hyperbola equation, i.e.
${
\Rightarrow (2x - y - 3)(3x + y - 7) + k = 0 \\
\Rightarrow (2x - y - 3)\left( {3x + y - 7} \right) - 6 = 0 \\
\Rightarrow 6{x^2} + 2xy - 14x - 3xy - {y^2} + 7y - 9x - 3y + 21 - 6 = 0 \\
} $
$ \Rightarrow 6{x^2} - {y^2} - xy - 23x + 4y + 15 = 0$
Hence $6{x^2} - {y^2} - xy - 23x + 4y + 15 = 0$ is the required hyperbola equation.
Note: The question is related to the coordinate chapter and conic section. The Conic section is a huge chapter including the topics of circle, ellipse, parabola, hyperbola. To solve questions related to them, one should know each and every point of their properties and terms.
Hyperbola is a collection of points in a plane such that there is a constant distance between two fixed points and each point. Hyperbola is made up of two similar curves that resemble a parabola.
Complete step-by-step answer:
We know that –
Equation of hyperbola differs from the joint equation of its asymptotes by a constant.
Equation of hyperbola –
$ \Rightarrow $(product of asymptote) $ + $constant$\left( k \right)$$ \Rightarrow $$0$
Given –
Asymptote equations are –
${
2x - y = 3 \\
\Rightarrow 2x - y - 3 = 0 \\
\therefore \left( {2x - y - 3} \right)\left( {3x + y - 7} \right) + k = 0..........(i) \\
} $
And,
${
3x + y = 7 \\
\Rightarrow 3x + y - 7 = 0 \\
} $
Now, it is given that hyperbola passes through $\left( {1,1} \right)$
$\therefore $Putting $\left( {x.y} \right) = \left( {1,1} \right)$ in equation $(i)$
${
\Rightarrow (2 - 1 - 3)(3 + 1 - 7) + k = 0 \\
\Rightarrow ( - 2 \times - 3) + k = 0 \\
\Rightarrow k = - 6 \\
} $
$\therefore $Putting $k = - 6$ in require hyperbola equation, i.e.
${
\Rightarrow (2x - y - 3)(3x + y - 7) + k = 0 \\
\Rightarrow (2x - y - 3)\left( {3x + y - 7} \right) - 6 = 0 \\
\Rightarrow 6{x^2} + 2xy - 14x - 3xy - {y^2} + 7y - 9x - 3y + 21 - 6 = 0 \\
} $
$ \Rightarrow 6{x^2} - {y^2} - xy - 23x + 4y + 15 = 0$
Hence $6{x^2} - {y^2} - xy - 23x + 4y + 15 = 0$ is the required hyperbola equation.
Note: The question is related to the coordinate chapter and conic section. The Conic section is a huge chapter including the topics of circle, ellipse, parabola, hyperbola. To solve questions related to them, one should know each and every point of their properties and terms.
Hyperbola is a collection of points in a plane such that there is a constant distance between two fixed points and each point. Hyperbola is made up of two similar curves that resemble a parabola.
Recently Updated Pages
Write structures of the following compounds i 2 Chloro3methylpentane class 11 chemistry CBSE

What is BLO What is the full form of BLO class 8 social science CBSE

Explain the Treaty of Vienna of 1815 class 10 social science CBSE

A Paragraph on Pollution in about 100-150 Words

XIX+XXX A 49 B 51 C 55 D 44 class 5 maths CBSE

If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

What do you mean by retardation What is its SI uni class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Difference between physical and chemical change class 11 chemistry CBSE

