How do you find the exact value of $\ln {e^3} - \ln e$ ?

Hint: For solving this particular problem we will use ${\log _e}{a^b} = b{\log _e}a$ , exponent rule may be used if $a$ is greater than zero. For simplifying the equation , we will use a logarithm property that is \[{\log _e}e = \ln e\] logarithm with base $e$ is equivalent to the natural logarithm .

Formula used:
We used logarithm property i.e., ${\log _e}{a^b} = b{\log _e}a$ , exponent rule may be used if $a$ is greater than zero. For simplifying the equation , we will use a logarithm property that is \[{\log _e}e = \ln e\] logarithm with base $e$ is equivalent to the natural logarithm .
We also used the identity ${\log _x}x = 1$ , this will always give us one .

Complete step by step solution:
Given $\ln {e^3} - \ln e$
We have to find the exact value of the given expression.
Now applying the identity ${\log _e}{a^b} = b{\log _e}a$ , we will get the following result ,
$ \Rightarrow 3\ln e - \ln e = 2\ln e$
We also know that \[{\log _e}e = \ln e\] logarithm with base $e$ is equivalent to the natural logarithm ,
Therefore, we can write ,
$ = 2{\log _e}e$
Now using the identity ${\log _x}x = 1$ , we will get the following result ,
$ = 2$

Therefore, we get the required result that is 2.

Note: The logarithm function says $\log x$ is only defined when $x$ is greater than zero. While defining logarithm function one should remember that the base of the log must be a positive real number and not equals to one . At the end we must recall that the logarithm function says $\log x$ is only defined when $x$is greater than zero. While performing logarithm properties we have to remember certain conditions , our end result must satisfy the domain of that logarithm .