How do you find the exact functional value \[\cos {25^ \circ }\cos {15^ \circ } - \sin {25^ \circ }\sin {15^ \circ }\]using the cosine sum (or) difference identity?
Answer
629.7k+ views
Hint: The given question describes the operation of using addition/ subtraction/ multiplication/ division. Also, in this question, we would use the trigonometric formula related to the given question. To solve the given question we would compare the given equation with the cosine sum (or) difference identity. After comparing the two-equation we would find the value of variables in the equation. Also, remind the basic trigonometric table value and related formula to find the value of the given equation.
Complete answer:
The given question is shown below,
\[\cos {25^ \circ }\cos {15^ \circ } - \sin {25^ \circ }\sin {15^ \circ } = ? \to \left( 1 \right)\]
To simplify the given question we have to compare the above equation with the cosine sum (or) difference identity which is given below,
\[\cos (a + b) = \cos a\cos b - \sin a\sin b\]
It also can be written as,
\[\cos a\cos b - \sin a\sin b = \cos (a + b) \to \left( 2 \right)\]
Let’s compare the equation (1) and (2), we get
\[
\left( 1 \right) \to \cos {25^ \circ }\cos {15^ \circ } - \sin {25^ \circ }\sin {15^ \circ } = ? \\
\left( 2 \right) \to \cos a\cos b - \sin a\sin b = \cos (a + b) \\
\]
By comparing the above two equations we get, the value of \[a\] is \[25\] and the value of \[b\] is\[15\].
By substituting the value of \[a\] and \[b\] in the equation\[(2)\], we get
\[\cos {25^ \circ }\cos {15^ \circ } - \sin {25^ \circ }\sin {15^ \circ } = \cos ({25^ \circ } + {15^ \circ })\]
It also can be written as,
\[\cos {25^ \circ }\cos {15^ \circ } - \sin {25^ \circ }\sin {15^ \circ } = \cos ({40^ \circ })\]
So, we get
\[\cos ({40^ \circ }) = 0.766\](Using calculator in degree mode)
So, the final answer is \[\cos {25^ \circ }\cos {15^ \circ } - \sin {25^ \circ }\sin {15^ \circ } = 0.766\]
Note: In this type of question we would use the operation of addition/ subtraction/ multiplication/ division. After that, we would try to compare the given question with the cosine sum (or) difference identity. When finding \[\cos \]value in the degree we should select the degree mode in the calculator. Also, note that \[\cos \left( { - \theta } \right)\] is \[\cos \left( \theta \right)\] and \[\sin ( - \theta )\] is \[\sin (\theta )\]. If the \[\theta \] value is in decimal we should use the calculator in radian mode.
Complete answer:
The given question is shown below,
\[\cos {25^ \circ }\cos {15^ \circ } - \sin {25^ \circ }\sin {15^ \circ } = ? \to \left( 1 \right)\]
To simplify the given question we have to compare the above equation with the cosine sum (or) difference identity which is given below,
\[\cos (a + b) = \cos a\cos b - \sin a\sin b\]
It also can be written as,
\[\cos a\cos b - \sin a\sin b = \cos (a + b) \to \left( 2 \right)\]
Let’s compare the equation (1) and (2), we get
\[
\left( 1 \right) \to \cos {25^ \circ }\cos {15^ \circ } - \sin {25^ \circ }\sin {15^ \circ } = ? \\
\left( 2 \right) \to \cos a\cos b - \sin a\sin b = \cos (a + b) \\
\]
By comparing the above two equations we get, the value of \[a\] is \[25\] and the value of \[b\] is\[15\].
By substituting the value of \[a\] and \[b\] in the equation\[(2)\], we get
\[\cos {25^ \circ }\cos {15^ \circ } - \sin {25^ \circ }\sin {15^ \circ } = \cos ({25^ \circ } + {15^ \circ })\]
It also can be written as,
\[\cos {25^ \circ }\cos {15^ \circ } - \sin {25^ \circ }\sin {15^ \circ } = \cos ({40^ \circ })\]
So, we get
\[\cos ({40^ \circ }) = 0.766\](Using calculator in degree mode)
So, the final answer is \[\cos {25^ \circ }\cos {15^ \circ } - \sin {25^ \circ }\sin {15^ \circ } = 0.766\]
Note: In this type of question we would use the operation of addition/ subtraction/ multiplication/ division. After that, we would try to compare the given question with the cosine sum (or) difference identity. When finding \[\cos \]value in the degree we should select the degree mode in the calculator. Also, note that \[\cos \left( { - \theta } \right)\] is \[\cos \left( \theta \right)\] and \[\sin ( - \theta )\] is \[\sin (\theta )\]. If the \[\theta \] value is in decimal we should use the calculator in radian mode.
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