How do you find the distance between the points \[\left( { - 4,2} \right)\], \[\left( {4,17} \right)\]?
Answer
623.1k+ views
Hint: Here in this question, we have to find the distance between the two given coordinates. Take the coordinates of two points you want to find the distance between. Call one point. Point 1 \[\left( {{x_1},{y_1}} \right)\] and make the other Point 2 \[\left( {{x_2},{y_2}} \right)\]. Know the distance formula \[\sqrt {{{\left( {{x_2} - {x_1}} \right)}^2} + {{\left( {{y_2} - {y_1}} \right)}^2}} \] . This formula finds the length of a line that stretches between two points: Point 1 and Point 2.
Complete step-by-step solution:
The distance between two points is the length of the interval joining the two points. If the two points lie on the same horizontal or same vertical line. In general the distance can be found by subtracting the coordinates that are not the same.
The distance between two points of the \[xy\] -plane can be found using the distance formula. An ordered pair \[\left( {x,{\text{ }}y} \right)\] represents co-ordinate of the point, where x-coordinate (or abscissa) is the distance of the point from the centre and y-coordinate (or ordinate) is the distance of the point from the centre.
Formula to find Distance Between Two Points in 2d plane. Consider two points, point 1 \[\left( {{x_1},{y_1}} \right)\] and point 2 \[\left( {{x_2},{y_2}} \right)\] on the given coordinate axis.
The distance between these points is given as: \[d = \sqrt {{{\left( {{x_2} - {x_1}} \right)}^2} + {{\left( {{y_2} - {y_1}} \right)}^2}} \]
Now consider the given two coordinates, point 1 \[\left( { - 4,2} \right)\] and point 2 \[\left( {4,17} \right)\].
The distance between point 1 and point 2 is
\[ \Rightarrow \,\,d = \sqrt {{{\left( {4 - \left( { - 4} \right)} \right)}^2} + {{\left( {17 - 2} \right)}^2}} \]
\[ \Rightarrow \,\,d = \sqrt {{{\left( {4 + 4} \right)}^2} + {{\left( {17 - 2} \right)}^2}} \]
\[ \Rightarrow \,\,d = \sqrt {{{\left( 8 \right)}^2} + {{\left( {15} \right)}^2}} \]
\[ \Rightarrow \,\,d = \sqrt {64 + 225} \]
\[ \Rightarrow \,\,d = \sqrt {289} \]
As we know the 289 is the square number of 17, then
\[ \Rightarrow \,\,d = \sqrt {{{17}^2}} \]
\[\therefore \,\,d = 17\]
Hence, the distance between the points \[\left( { - 4,2} \right)\] and \[\left( {4,17} \right)\] is \[d = 17\].
Note: The distance is a length between the two points. In the geometry we have a formula to determine the distance between the points. While determining the distance between the points we consider the both values of x and the value of y. Where x and y are the coordinates.
Complete step-by-step solution:
The distance between two points is the length of the interval joining the two points. If the two points lie on the same horizontal or same vertical line. In general the distance can be found by subtracting the coordinates that are not the same.
The distance between two points of the \[xy\] -plane can be found using the distance formula. An ordered pair \[\left( {x,{\text{ }}y} \right)\] represents co-ordinate of the point, where x-coordinate (or abscissa) is the distance of the point from the centre and y-coordinate (or ordinate) is the distance of the point from the centre.
Formula to find Distance Between Two Points in 2d plane. Consider two points, point 1 \[\left( {{x_1},{y_1}} \right)\] and point 2 \[\left( {{x_2},{y_2}} \right)\] on the given coordinate axis.
The distance between these points is given as: \[d = \sqrt {{{\left( {{x_2} - {x_1}} \right)}^2} + {{\left( {{y_2} - {y_1}} \right)}^2}} \]
Now consider the given two coordinates, point 1 \[\left( { - 4,2} \right)\] and point 2 \[\left( {4,17} \right)\].
The distance between point 1 and point 2 is
\[ \Rightarrow \,\,d = \sqrt {{{\left( {4 - \left( { - 4} \right)} \right)}^2} + {{\left( {17 - 2} \right)}^2}} \]
\[ \Rightarrow \,\,d = \sqrt {{{\left( {4 + 4} \right)}^2} + {{\left( {17 - 2} \right)}^2}} \]
\[ \Rightarrow \,\,d = \sqrt {{{\left( 8 \right)}^2} + {{\left( {15} \right)}^2}} \]
\[ \Rightarrow \,\,d = \sqrt {64 + 225} \]
\[ \Rightarrow \,\,d = \sqrt {289} \]
As we know the 289 is the square number of 17, then
\[ \Rightarrow \,\,d = \sqrt {{{17}^2}} \]
\[\therefore \,\,d = 17\]
Hence, the distance between the points \[\left( { - 4,2} \right)\] and \[\left( {4,17} \right)\] is \[d = 17\].
Note: The distance is a length between the two points. In the geometry we have a formula to determine the distance between the points. While determining the distance between the points we consider the both values of x and the value of y. Where x and y are the coordinates.
Recently Updated Pages
Write structures of the following compounds i 2 Chloro3methylpentane class 11 chemistry CBSE

What is BLO What is the full form of BLO class 8 social science CBSE

Explain the Treaty of Vienna of 1815 class 10 social science CBSE

A Paragraph on Pollution in about 100-150 Words

XIX+XXX A 49 B 51 C 55 D 44 class 5 maths CBSE

If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

What do you mean by retardation What is its SI uni class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Difference between physical and chemical change class 11 chemistry CBSE

