How do you find the derivative of ${e^{ - 2t}}$?
Answer
622.5k+ views
Hint: Here, we find the first order of the derivative and by using the chain rule of the composite function. First of all we will apply the derivative of the given power in the function and then by using the chain rule will take the derivative of the function and then the derivative of the angle.
Complete step-by-step solution:
Take the given expression –
$f(t) = {e^{ - 2t}}$
Take derivative of the given function –
$f'(t) = \dfrac{d}{{dt}}{e^{ - 2t}}$
Place the value of the derivative in the above equation, and also apply chain rule to find the derivative of the power in the given expression.
$f'(t) = {e^{ - 2t}}\dfrac{d}{{dt}}( - 2t)$
Now again place the derivative value in the above expression
$f'(t) = - 2.{e^{ - 2t}}$
Now, using the law of power and exponent, when there is negative power then it will become positive when placed in the form of fraction. When there is negative power in the numerator then it will become positive in the denominator.
$f'(t) = \dfrac{{ - 2}}{{{e^{2t}}}}$
This is the required solution.
Additional Information: In mathematics, integration is the concept of calculus and it is the act of finding the integrals. One can find the instantaneous rate of change of the function at a point by finding the derivative of that function and placing it in the x-value of the point. Instantaneous rate of change of the function can be represented by the slope of the line, which says how much the function is increasing or decreasing as the x-values change.
Note: Know the difference between the differentiation and the integration and apply the formula accordingly. Differentiation can be represented as the rate of change of the function, whereas integration represents the sum of the function over the range. They are inverses of each other
Complete step-by-step solution:
Take the given expression –
$f(t) = {e^{ - 2t}}$
Take derivative of the given function –
$f'(t) = \dfrac{d}{{dt}}{e^{ - 2t}}$
Place the value of the derivative in the above equation, and also apply chain rule to find the derivative of the power in the given expression.
$f'(t) = {e^{ - 2t}}\dfrac{d}{{dt}}( - 2t)$
Now again place the derivative value in the above expression
$f'(t) = - 2.{e^{ - 2t}}$
Now, using the law of power and exponent, when there is negative power then it will become positive when placed in the form of fraction. When there is negative power in the numerator then it will become positive in the denominator.
$f'(t) = \dfrac{{ - 2}}{{{e^{2t}}}}$
This is the required solution.
Additional Information: In mathematics, integration is the concept of calculus and it is the act of finding the integrals. One can find the instantaneous rate of change of the function at a point by finding the derivative of that function and placing it in the x-value of the point. Instantaneous rate of change of the function can be represented by the slope of the line, which says how much the function is increasing or decreasing as the x-values change.
Note: Know the difference between the differentiation and the integration and apply the formula accordingly. Differentiation can be represented as the rate of change of the function, whereas integration represents the sum of the function over the range. They are inverses of each other
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
Find the value of the expression given below sin 30circ class 11 maths CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

