Find 4 different numbers whose average works up to 50.
Answer
569.7k+ views
Hint: We first explain the general condition for finding average. Then we use the particular form for 4 different numbers. We find 4 different numbers and show that their average works up to 50.
Complete step-by-step answer:
Sample average can be expressed as $\overline{x}=\dfrac{\sum{{{x}_{i}}}}{n}$ for $n$ inputs. For 4 different numbers $a,b,c,d$, the average works up as $\overline{x}=\dfrac{a+b+c+d}{4}$.
We have to find 4 different numbers whose average works up to 50.
We take 31, 66, 57, 46. We now try to find the average.
So, the sum is $31+66+57+46=200$.
The average will be $\dfrac{200}{4}=50$.
Therefore, the average of 4 different numbers 31, 66, 57, 46 is 50.
So, the correct answer is “31, 66, 57, 46”.
Note: These all-required attributes are the measurement of central tendency. The sample mean is part of the central tendency. An outlier can affect the average by being unusually small or unusually large. The mean is non-resistant. That means, it's affected by outliers. More specifically, the mean will want to move towards the outlier.
Complete step-by-step answer:
Sample average can be expressed as $\overline{x}=\dfrac{\sum{{{x}_{i}}}}{n}$ for $n$ inputs. For 4 different numbers $a,b,c,d$, the average works up as $\overline{x}=\dfrac{a+b+c+d}{4}$.
We have to find 4 different numbers whose average works up to 50.
We take 31, 66, 57, 46. We now try to find the average.
So, the sum is $31+66+57+46=200$.
The average will be $\dfrac{200}{4}=50$.
Therefore, the average of 4 different numbers 31, 66, 57, 46 is 50.
So, the correct answer is “31, 66, 57, 46”.
Note: These all-required attributes are the measurement of central tendency. The sample mean is part of the central tendency. An outlier can affect the average by being unusually small or unusually large. The mean is non-resistant. That means, it's affected by outliers. More specifically, the mean will want to move towards the outlier.
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