How do you factor ${{x}^{2}}+10x-11$ ?
(a) Factor by grouping
(b) Zero putting
(c) Guessing the factors
(d) None of the above

Hint: To find the factor of the given equation ${{x}^{2}}+10x-11$, we will try to factorize it by grouping them among terms. We will start off with multiplying the coefficients of the first and last terms and then factorize them to get the middle term of the equation. Then by taking the proper terms common we can get the needed answer and factorization.

Complete step by step solution:
We have our given equation as, ${{x}^{2}}+10x-11$and we are to factorize this equation.
So, to start with,
${{x}^{2}}+10x-11$
As, we are trying to factorize this with grouping, we will write, $10x$ as $11x-x$ ,
$\Rightarrow {{x}^{2}}+11x-x-11$
In the next step we will take common term from the terms,
$\Rightarrow x(x+11)-1(x+11)$
Bringing them together,
$\Rightarrow (x-1)(x+11)$
So, now we have,
$\Rightarrow (x-1)(x+11)$

So, the correct answer is “Option a”.

Note: A polynomial ${{x}^{2}}+10x-11$ can be written as a product of two or more polynomials of degree less than or equal to that of it. Each polynomial involved in the product will be a factor of it. Monomials can be factorized in the same way as integers, just by writing the monomial as the product of its constituent prime factors. In the case of monomials, these prime factors can be integers as well as other monomials which cannot be factored further.