Explain Bohr-Bury scheme.

Hint:The Bohr-Bury scheme describes the arrangement of electrons and the number of electrons that can accommodate in a shell or orbital. One can elaborate electrons that can accommodate in each shell.

Complete step by step answer:1) First of all we will learn the concept of the Bohr-Bury scheme where it states as the maximum number of electrons that could be present in a shell is given by a formula $2{n^2}$.
Where ${\text{n}}$ is the orbit or shell number of that atom.
2) Now if we apply this formula for shells we will get the maximum occupancy as below,
For first orbit i.e. K shell $ = 2{n^2} = 2 \times {1^2} = 2$ electrons.
For second orbit i.e. L shell $ = 2{n^2} = 2 \times {2^2} = 8$ electrons.
For the third orbit i.e. M shell $ = 2{n^2} = 2 \times {3^2} = 18$ electrons.
For fourth orbit i.e. N shell $ = 2{n^2} = 2 \times {4^2} = 32$ electrons.
3) The Bohr-Bury scheme further elaborates as the electrons in an orbit must be filled in a stepwise manner, that is one can not fill the electrons in a higher shell if the lower shell is not fully filled.
4) Electrons revolve around the nucleus in a specific fixed path and that path is called an orbit. There is a certain limit of each orbit that can have a certain number of electrons.
5) The Bohr-bury scheme also elaborates its theory as an electron when revolving in an orbit does not lose energy which means it sustains its energy.

Note:In an atom, there are orbits or shells as K, L, M, N from lower to higher respectively. Each shell or orbit has a subshell named as s, p, d, f which has ${\text{2, 6, 10, 14}}$ electrons occupancy respectively.