Evaluate the value of $\sin 45^\circ + \cos 45^\circ $ .
Answer
646.2k+ views
Hint:
Here, it is asked to find the value of $\sin 45^\circ + \cos 45^\circ $.
So, firstly, find the values of $\sin 45^\circ $ and $\cos 45^\circ $.
Thus, on obtaining the values of $\sin 45^\circ $ and $\cos 45^\circ $ , substitute the values in the given equation.
Hence, the required answer is obtained.
Complete step by step solution:
Here, we are asked to find the value of $\sin 45^\circ + \cos 45^\circ $ .
To do so, we firstly need the values of $\sin 45^\circ $ and $\cos 45^\circ $ .
We know that, $\sin 45^\circ = \dfrac{1}{{\sqrt 2 }}$ and $\cos 45^\circ = \dfrac{1}{{\sqrt 2 }}$ .
Now, substituting $\sin 45^\circ = \dfrac{1}{{\sqrt 2 }}$ and $\cos 45^\circ = \dfrac{1}{{\sqrt 2 }}$ in the given trigonometric equation.
$\therefore \sin 45^\circ + \cos 45^\circ = \dfrac{1}{{\sqrt 2 }} + \dfrac{1}{{\sqrt 2 }}$
$
= \dfrac{{1 + 1}}{{\sqrt 2 }} \\
= \dfrac{2}{{\sqrt 2 }} \\
= \sqrt 2
$
Thus, we get the value of $\sin 45^\circ + \cos 45^\circ $ as $\sqrt 2 $.
Note:
Some useful values to be remembered:
Here, it is asked to find the value of $\sin 45^\circ + \cos 45^\circ $.
So, firstly, find the values of $\sin 45^\circ $ and $\cos 45^\circ $.
Thus, on obtaining the values of $\sin 45^\circ $ and $\cos 45^\circ $ , substitute the values in the given equation.
Hence, the required answer is obtained.
Complete step by step solution:
Here, we are asked to find the value of $\sin 45^\circ + \cos 45^\circ $ .
To do so, we firstly need the values of $\sin 45^\circ $ and $\cos 45^\circ $ .
We know that, $\sin 45^\circ = \dfrac{1}{{\sqrt 2 }}$ and $\cos 45^\circ = \dfrac{1}{{\sqrt 2 }}$ .
Now, substituting $\sin 45^\circ = \dfrac{1}{{\sqrt 2 }}$ and $\cos 45^\circ = \dfrac{1}{{\sqrt 2 }}$ in the given trigonometric equation.
$\therefore \sin 45^\circ + \cos 45^\circ = \dfrac{1}{{\sqrt 2 }} + \dfrac{1}{{\sqrt 2 }}$
$
= \dfrac{{1 + 1}}{{\sqrt 2 }} \\
= \dfrac{2}{{\sqrt 2 }} \\
= \sqrt 2
$
Thus, we get the value of $\sin 45^\circ + \cos 45^\circ $ as $\sqrt 2 $.
Note:
Some useful values to be remembered:
| $0^\circ $ | $30^\circ $ | $45^\circ $ | $60^\circ $ | $90^\circ $ | |
| $\sin \theta $ | 0 | $\dfrac{1}{2}$ | $\dfrac{1}{{\sqrt 2 }}$ | $\dfrac{{\sqrt 3 }}{2}$ | 1 |
| $\cos \theta $ | 1 | $\dfrac{{\sqrt 3 }}{2}$ | $\dfrac{1}{{\sqrt 2 }}$ | $\dfrac{1}{2}$ | 0 |
| $\tan \theta $ | 0 | $\dfrac{1}{{\sqrt 3 }}$ | 1 | \[\sqrt 3 \] | Not defined |
| $\operatorname{cosec} \theta $ | Not defined | 2 | $\sqrt 2 $ | $\dfrac{2}{{\sqrt 3 }}$ | 1 |
| $\sec \theta $ | 1 | $\dfrac{2}{{\sqrt 3 }}$ | $\sqrt 2 $ | 2 | Not defined |
| $\cot \theta $ | Not defined | \[\sqrt 3 \] | 1 | $\dfrac{1}{{\sqrt 3 }}$ | 0 |
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