What does not change on changing temperature
A) Mole fraction
B) Normality
C) Molality
D) none of these
Answer
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Hint: As we know that in chemistry, the concentration of the solution is very important. The strength of the solution is very important for inhale solution and medicinal chemistry. There are different ways of representing the concentration of solutions. There are molality, molarity, normality formality, mole fraction, mass percentage, volume percentage, mass by volume and parts per million.
Complete answer:
Mole fraction is independent of the temperature.
Normality is dependent on the temperature by volume.
Molality is independent of the temperature.
According to the above discussion, we conclude mole fraction and molality do not change on changing temperature.
So, the correct answer is “Option A&C”.
Additional information:
The normality of the solution depends on the number of the gram equivalents of solute and the volume of the solution in litres. The normality of the solution is equal to the ratio of the number of the gram equivalent of the solute to the volume of the solution in litres. The symbol of normality is N.
\[{\text{Normality = }}\dfrac{{{\text{number of gram equivalent of the solute}}}}{{{\text{volume of the solution litre}}}}\]
The gram equivalent of the acid depends on the molecular mass of the acid divided by the basicity of the acid. The basicity of the acid is nothing but the number of hydrogen ions able to donate the acid in aqueous medium. The gram equivalent of the acid is equal to the ratio of the molecular mass of the acid to the basicity of the acid. In the acid base concept the hydrogen ion is very important. The acids are proton or hydrogen ion donors. The bases are hydrogen ions or proton acceptor in the reaction. The basicity of the acid and the acidity of the base is dependent on the hydrogen ion in the molecule. The molecular weight of the molecule is the sum of the atomic weight of the atoms in the molecule.
Note:
We need to know that the molarity of the solution depends on the number moles of the solute and the volume of the solution in litres. The molarity of the solution is equal to the ratio of the number of moles of the solute to the volume of the solution in litres. The symbol of molarity is M.
\[{\text{Molarity = }}\dfrac{{{\text{number of moles of the solute}}}}{{{\text{volume of the solution litre}}}}\]
Complete answer:
Mole fraction is independent of the temperature.
Normality is dependent on the temperature by volume.
Molality is independent of the temperature.
According to the above discussion, we conclude mole fraction and molality do not change on changing temperature.
So, the correct answer is “Option A&C”.
Additional information:
The normality of the solution depends on the number of the gram equivalents of solute and the volume of the solution in litres. The normality of the solution is equal to the ratio of the number of the gram equivalent of the solute to the volume of the solution in litres. The symbol of normality is N.
\[{\text{Normality = }}\dfrac{{{\text{number of gram equivalent of the solute}}}}{{{\text{volume of the solution litre}}}}\]
The gram equivalent of the acid depends on the molecular mass of the acid divided by the basicity of the acid. The basicity of the acid is nothing but the number of hydrogen ions able to donate the acid in aqueous medium. The gram equivalent of the acid is equal to the ratio of the molecular mass of the acid to the basicity of the acid. In the acid base concept the hydrogen ion is very important. The acids are proton or hydrogen ion donors. The bases are hydrogen ions or proton acceptor in the reaction. The basicity of the acid and the acidity of the base is dependent on the hydrogen ion in the molecule. The molecular weight of the molecule is the sum of the atomic weight of the atoms in the molecule.
Note:
We need to know that the molarity of the solution depends on the number moles of the solute and the volume of the solution in litres. The molarity of the solution is equal to the ratio of the number of moles of the solute to the volume of the solution in litres. The symbol of molarity is M.
\[{\text{Molarity = }}\dfrac{{{\text{number of moles of the solute}}}}{{{\text{volume of the solution litre}}}}\]
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