How does concentration affect equilibrium?

Hint:The question is related to an equilibrium system and the equilibrium condition of the system changes with changes in the various parameters. We could use Le-Chatelier's principle to explain how concentration affects the system.

Complete step-by-step answer:So analyzing the question, we know that we have to comment on how the concentration will affect the equilibrium state of a system.
Before discussing the solution, we should have an idea about the equilibrium system and the parameters that can bring a change in the system.
A system in which the rate of formation of the products and the decomposition of the products into reactants takes place at the same rate, then that system is called an equilibrium system. Hence we could not trace any physical change happening there but the reaction is continuously taking place.
The parameters like concentration, temperature, concentration, etc. make a change in the rate of forward and reverse reaction happening which affects the equilibrium position.
To predict the changes in the rate of the change of the reaction, we use Le-Chatelier's principle.
According to Le-Chatelier's principle if the concentration increases then the reaction will be carried out in that direction which will counteract that change.
If the concentration of the reactants is increased the forward reaction will proceed with a higher rate and more products will be formed to re-establish the equilibrium. And if the concentration of the products increases then the reaction will take place in that reaction which will yield a greater concentration of reactants i.e. the reverse reaction is favored.

Note:If the reactant concentration is decreased then the decomposition reaction of the product occurs and more reactants are formed ie the reverse reaction will be favored. If the concentration is decreased i.e. if we remove the product then the concentration of the product will decrease and the forward reaction will take place to form more amounts of products.