How do you divide $1\dfrac{3}{4}\div 4\dfrac{1}{3}$ ?

Hint: Both fraction in the term $1\dfrac{3}{4}\div 4\dfrac{1}{3}$. First, we have to convert both the mixed fraction to simple fraction. $1\dfrac{3}{4}$ is equal to $\dfrac{7}{4}$ and $4\dfrac{1}{3}$ is equal to $\dfrac{13}{3}$ . We know that fraction a divided by fraction b is equal to a multiplied by reciprocal of b. so $\dfrac{7}{4}$ divided by $\dfrac{13}{3}$ is equal to product of $\dfrac{7}{4}$ and reciprocal of $\dfrac{13}{3}$ which is equal to $\dfrac{3}{13}$ .

Complete step by step answer:
We have to solve $1\dfrac{3}{4}\div 4\dfrac{1}{3}$ ?
Let’s convert $1\dfrac{3}{4}$ and $4\dfrac{1}{3}$ to a simple fraction. $1\dfrac{3}{4}$is equal to $\dfrac{7}{4}$ and $4\dfrac{1}{3}$ is equal to $\dfrac{13}{3}$
$\Rightarrow 1\dfrac{3}{4}\div 4\dfrac{1}{3}=\dfrac{7}{4}\div \dfrac{13}{3}$
We know that fraction a divided by fraction b is equal to a multiplied by reciprocal of b
Reciprocal of $\dfrac{13}{3}$ is equal to $\dfrac{3}{13}$
$1\dfrac{3}{4}\div 4\dfrac{1}{3}$ is equal to multiplication of $\dfrac{7}{4}$ and $\dfrac{3}{13}$
$\Rightarrow 1\dfrac{3}{4}\div 4\dfrac{1}{3}=\dfrac{7}{4}\times \dfrac{3}{13}$
Now we can just multiply numerator and denominator
$\Rightarrow 1\dfrac{3}{4}\div 4\dfrac{1}{3}=\dfrac{21}{52}$
$\dfrac{21}{52}$ is the quotient when we divide $1\dfrac{3}{4}$ by $4\dfrac{1}{3}$

Note:
Product of a number and its reciprocal is always equal to 1. We can not find the reciprocal of 0 because there does not exist a number such that the product of the number and 0 is equal to 1. Always remember that in a division we can not make the divisor 0, because we can divide anything by 0. So we can not make the denominator of a fraction 0 and we can not make a numerator of divisor 0. If the numerator of the divisor is equal to 0 then the value of divisor will also 0.