How do you derive a function composed of a division and a multiplication? Do you use the quotient rule or the product rule? Ex: $ f\left( x \right)={{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{3}}\left( 7{{x}^{6}}+4{{x}^{6}}-5{{x}^{2}} \right)$ ?
Answer
616.8k+ views
Hint: For this question, first you need to separate the equation into two parts. Then you need to find the derivative of the first part using the quotient rule of differentiation. Then you can use the product rule to find the derivative of the total question.
Complete step by step answer:
According to the problem, we are asked to derive a function composed of a division and a multiplication that is $ f\left( x \right)={{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{3}}\left( 7{{x}^{6}}+4{{x}^{6}}-5{{x}^{2}} \right)$.
We number this equation 1.
$ f\left( x \right)={{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{3}}\left( 11{{x}^{6}}-5{{x}^{2}} \right)$------ (1)
Now we divide it into two parts. The first part is $ {{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{3}}$ and the second part is $ \left( 7{{x}^{6}}+4{{x}^{6}}-5{{x}^{2}} \right)$.
Now we find the derivative of the first part using the quotient rule:
$ \Rightarrow \dfrac{d{{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{3}}}{dx}=3{{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{2}}\dfrac{d{{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{2}}}{dx}$
$ \Rightarrow \dfrac{d{{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{3}}}{dx}=3{{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{2}}\dfrac{d\left( \dfrac{-{{x}^{2}}+{{x}^{-1}}}{2.5{{x}^{2}}} \right)}{dx}$
Now, we use the quotient rule in the differentiation. Therefore we get,
$ \Rightarrow \dfrac{d{{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{3}}}{dx}=3{{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{2}}\left( -\left( \dfrac{2.5{{x}^{2}}\left( 2x+\dfrac{1}{{{x}^{2}}} \right)-5x\left( {{x}^{2}}-\dfrac{1}{x} \right)}{6.25{{x}^{4}}} \right) \right)$
$ \Rightarrow \dfrac{d{{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{3}}}{dx}=3{{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{2}}\left( -\left( \dfrac{5{{x}^{3}}+2.5-5{{x}^{2}}+5}{6.25{{x}^{4}}} \right) \right)$
$ \Rightarrow \dfrac{d{{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{3}}}{dx}=3{{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{2}}\left( -\dfrac{7.5}{6.25{{x}^{4}}} \right)$
$ \Rightarrow \dfrac{d{{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{3}}}{dx}=3{{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{2}}\left( -\dfrac{1.2}{{{x}^{4}}} \right)$----- (2)
$ \Rightarrow f'\left( x \right)=\left( 11{{x}^{6}}-5{{x}^{2}} \right)\left( 3{{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{2}}\left( -\dfrac{1.2}{{{x}^{4}}} \right) \right)+{{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{3}}\left( 66{{x}^{5}}-10x \right)$--- final answer.
Therefore, we have derived the derivative of a function composed of a division and a multiplication that is $ f\left( x \right)={{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{3}}\left( 7{{x}^{6}}+4{{x}^{6}}-5{{x}^{2}} \right)$.
Therefore, after all the derivation, we get the derivative of a function composed of a division and a multiplication that is $ f\left( x \right)={{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{3}}\left( 7{{x}^{6}}+4{{x}^{6}}-5{{x}^{2}} \right)$ as $ f'\left( x \right)=\left( 11{{x}^{6}}-5{{x}^{2}} \right)\left( 3{{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{2}}\left( -\dfrac{1.2}{{{x}^{4}}} \right) \right)+{{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{3}}\left( 66{{x}^{5}}-10x \right)$.
Note:
While doing the questions of this type, we need the derivatives of the basic polynomials. Also, we should be careful while doing all the substitutions. The derivatives of all the polynomials can be checked by using the integration.
Complete step by step answer:
According to the problem, we are asked to derive a function composed of a division and a multiplication that is $ f\left( x \right)={{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{3}}\left( 7{{x}^{6}}+4{{x}^{6}}-5{{x}^{2}} \right)$.
We number this equation 1.
$ f\left( x \right)={{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{3}}\left( 11{{x}^{6}}-5{{x}^{2}} \right)$------ (1)
Now we divide it into two parts. The first part is $ {{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{3}}$ and the second part is $ \left( 7{{x}^{6}}+4{{x}^{6}}-5{{x}^{2}} \right)$.
Now we find the derivative of the first part using the quotient rule:
$ \Rightarrow \dfrac{d{{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{3}}}{dx}=3{{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{2}}\dfrac{d{{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{2}}}{dx}$
$ \Rightarrow \dfrac{d{{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{3}}}{dx}=3{{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{2}}\dfrac{d\left( \dfrac{-{{x}^{2}}+{{x}^{-1}}}{2.5{{x}^{2}}} \right)}{dx}$
Now, we use the quotient rule in the differentiation. Therefore we get,
$ \Rightarrow \dfrac{d{{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{3}}}{dx}=3{{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{2}}\left( -\left( \dfrac{2.5{{x}^{2}}\left( 2x+\dfrac{1}{{{x}^{2}}} \right)-5x\left( {{x}^{2}}-\dfrac{1}{x} \right)}{6.25{{x}^{4}}} \right) \right)$
$ \Rightarrow \dfrac{d{{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{3}}}{dx}=3{{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{2}}\left( -\left( \dfrac{5{{x}^{3}}+2.5-5{{x}^{2}}+5}{6.25{{x}^{4}}} \right) \right)$
$ \Rightarrow \dfrac{d{{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{3}}}{dx}=3{{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{2}}\left( -\dfrac{7.5}{6.25{{x}^{4}}} \right)$
$ \Rightarrow \dfrac{d{{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{3}}}{dx}=3{{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{2}}\left( -\dfrac{1.2}{{{x}^{4}}} \right)$----- (2)
$ \Rightarrow f'\left( x \right)=\left( 11{{x}^{6}}-5{{x}^{2}} \right)\left( 3{{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{2}}\left( -\dfrac{1.2}{{{x}^{4}}} \right) \right)+{{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{3}}\left( 66{{x}^{5}}-10x \right)$--- final answer.
Therefore, we have derived the derivative of a function composed of a division and a multiplication that is $ f\left( x \right)={{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{3}}\left( 7{{x}^{6}}+4{{x}^{6}}-5{{x}^{2}} \right)$.
Therefore, after all the derivation, we get the derivative of a function composed of a division and a multiplication that is $ f\left( x \right)={{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{3}}\left( 7{{x}^{6}}+4{{x}^{6}}-5{{x}^{2}} \right)$ as $ f'\left( x \right)=\left( 11{{x}^{6}}-5{{x}^{2}} \right)\left( 3{{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{2}}\left( -\dfrac{1.2}{{{x}^{4}}} \right) \right)+{{\left( \dfrac{{{x}^{2}}-5{{x}^{-1}}}{\left( 5x \right)\left( -.5x \right)} \right)}^{3}}\left( 66{{x}^{5}}-10x \right)$.
Note:
While doing the questions of this type, we need the derivatives of the basic polynomials. Also, we should be careful while doing all the substitutions. The derivatives of all the polynomials can be checked by using the integration.
Recently Updated Pages
Write structures of the following compounds i 2 Chloro3methylpentane class 11 chemistry CBSE

What is BLO What is the full form of BLO class 8 social science CBSE

Explain the Treaty of Vienna of 1815 class 10 social science CBSE

A Paragraph on Pollution in about 100-150 Words

XIX+XXX A 49 B 51 C 55 D 44 class 5 maths CBSE

If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

What do you mean by retardation What is its SI uni class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Difference between physical and chemical change class 11 chemistry CBSE

