How do you convert \[\left( 0,\dfrac{\pi }{6} \right)\] to rectangular form?
Answer
610.5k+ views
Hint: In this problem, we have to convert the given polar form to the rectangular form. We are given a polar coordinate to convert them into a rectangular coordinate. We can use the conversion formula to convert from polar coordinates to rectangular coordinates. We can substitute the value of r and \[\theta \] in the conversion formula which is given in this problem as polar coordinate, to find the rectangular coordinates.
Complete step by step solution:
We know that the given polar coordinates are,
\[\left( 0,\dfrac{\pi }{6} \right)\]
Where, r = 0, \[\theta =\dfrac{\pi }{6}\]
We know that the conversion formula to convert from polar coordinates to rectangular coordinates is,
\[\begin{align}
& x=r\cos \theta \\
& y=r\sin \theta \\
\end{align}\]
We can now substitute the value of r and \[\theta \] in the above formula, we get
\[\begin{align}
& \Rightarrow x=0\cos \left( \dfrac{\pi }{6} \right) \\
& \Rightarrow y=0\sin \left( \dfrac{\pi }{6} \right) \\
\end{align}\]
We can now simplify the above step, as we multiply any number with 0, the answer will be zero.
\[\begin{align}
& \Rightarrow x=0 \\
& \Rightarrow y=0 \\
\end{align}\]
We can see that this could have been solved by just noting that the radius is zero and this means we are at the origin.
Therefore, the rectangular coordinates are \[\left( 0,0 \right)\].
Note: Students make mistakes while writing the conversion formula to convert from polar form to a rectangular form, we should know that the polar coordinates are given as \[\left( r,\theta \right)\] format. We should know that in case we are given a number instead of 0, then we will have to find the trigonometric values for the given degree and we have to solve for x and y coordinates.
Complete step by step solution:
We know that the given polar coordinates are,
\[\left( 0,\dfrac{\pi }{6} \right)\]
Where, r = 0, \[\theta =\dfrac{\pi }{6}\]
We know that the conversion formula to convert from polar coordinates to rectangular coordinates is,
\[\begin{align}
& x=r\cos \theta \\
& y=r\sin \theta \\
\end{align}\]
We can now substitute the value of r and \[\theta \] in the above formula, we get
\[\begin{align}
& \Rightarrow x=0\cos \left( \dfrac{\pi }{6} \right) \\
& \Rightarrow y=0\sin \left( \dfrac{\pi }{6} \right) \\
\end{align}\]
We can now simplify the above step, as we multiply any number with 0, the answer will be zero.
\[\begin{align}
& \Rightarrow x=0 \\
& \Rightarrow y=0 \\
\end{align}\]
We can see that this could have been solved by just noting that the radius is zero and this means we are at the origin.
Therefore, the rectangular coordinates are \[\left( 0,0 \right)\].
Note: Students make mistakes while writing the conversion formula to convert from polar form to a rectangular form, we should know that the polar coordinates are given as \[\left( r,\theta \right)\] format. We should know that in case we are given a number instead of 0, then we will have to find the trigonometric values for the given degree and we have to solve for x and y coordinates.
Recently Updated Pages
Write structures of the following compounds i 2 Chloro3methylpentane class 11 chemistry CBSE

What is BLO What is the full form of BLO class 8 social science CBSE

Explain the Treaty of Vienna of 1815 class 10 social science CBSE

A Paragraph on Pollution in about 100-150 Words

XIX+XXX A 49 B 51 C 55 D 44 class 5 maths CBSE

If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

What do you mean by retardation What is its SI uni class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Difference between physical and chemical change class 11 chemistry CBSE

