How do you convert $2.3\times{10^{ - 2}}$ in expanded notation?
Answer
620.4k+ views
Hint: First we will specify the expanded notation and then mention its format. Mention how to write the number in two ways that is in even and odd. Then we will mention all the steps required to convert a number from scientific notation.
Complete step-by-step solution:
We will start by explaining the expanded notation which is explained such as the notation which produces an expression which represents each place holder’s value. Standard notation is always represented by the sums of all the values multiplied by ten raised to the power of any number which should equal the original expression.
Now that you know that the degree of the constants is consecutively decreasing by one as one moves down every unit placeholder. Now if we look at our question $2.3\times{10^{ - 2}}$ we will turn the expression into decimal format.
$
\Rightarrow 2.3\times{10^{ - 2}} \\
\Rightarrow \dfrac{6}{{{{10}^2}}}x \\
\Rightarrow \dfrac{6}{{100}}x \\
\Rightarrow 0.06x \\
$
Now as this expression has one numerical value of $6$ which is occupying the hundredths place, so we multiply $6$ by ${10^{ - 2}}$ as this is equal to $0.06$. Now with regards to the algebraic terms, such as $x$ in our case, since these variables are unknown and can have any value, so they are left as it is.
Hence, the representation of $2.3\times {10^{ - 2}}$ in expanded notation is $0.06$.
Note: For square roots evaluate the reverse of a square. The square root symbol basically means the opposite of the $2$ symbol. Be careful while taking the square root and also consider the signs of the numbers. While moving the decimal always traces back to avoid any mistakes.
Complete step-by-step solution:
We will start by explaining the expanded notation which is explained such as the notation which produces an expression which represents each place holder’s value. Standard notation is always represented by the sums of all the values multiplied by ten raised to the power of any number which should equal the original expression.
Now that you know that the degree of the constants is consecutively decreasing by one as one moves down every unit placeholder. Now if we look at our question $2.3\times{10^{ - 2}}$ we will turn the expression into decimal format.
$
\Rightarrow 2.3\times{10^{ - 2}} \\
\Rightarrow \dfrac{6}{{{{10}^2}}}x \\
\Rightarrow \dfrac{6}{{100}}x \\
\Rightarrow 0.06x \\
$
Now as this expression has one numerical value of $6$ which is occupying the hundredths place, so we multiply $6$ by ${10^{ - 2}}$ as this is equal to $0.06$. Now with regards to the algebraic terms, such as $x$ in our case, since these variables are unknown and can have any value, so they are left as it is.
Hence, the representation of $2.3\times {10^{ - 2}}$ in expanded notation is $0.06$.
Note: For square roots evaluate the reverse of a square. The square root symbol basically means the opposite of the $2$ symbol. Be careful while taking the square root and also consider the signs of the numbers. While moving the decimal always traces back to avoid any mistakes.
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