Construct the following quadrilateral: Quadrilateral GOLD. OL\[ = 7.5\]cm, GL\[ = 6\]cm, GD\[ = 6\]cm, LD\[ = 5\]cm, and OD\[ = 10\]cm.
Answer
539.1k+ views
Hint: To construct any quadrilateral we need the value of sides which is given in the question.
In this question, you have to use a compass.
With the help of a compass, you have to take the value in the compass and mark the value with it and at last, join them.
Complete answer:
Given that,
OL\[ = 7.5\]cm, GL\[ = 6\]cm, GD\[ = 6\]cm, LD\[ = 5\]cm, and OD\[ = 10\]cm
First of all, draw a line segment which is OL\[ = 7.5\]cm
Now, take O as a centre with radius \[10\] cm and draw an arc and join OD.
Now, take L as a centre with radius \[5\] cm and draw an arc, which meets the previous arc at point D and join DL.
Now, Take L as centre with radius \[6\]cm and draw an arc and join GL
Now, Take D as centre with radius \[6\]cm and draw an arc, which meets the previous arc at point G.
Hence, the required quadrilateral GOLD is:
Note:
While constructing the arc student should keep in mind that they take the value in the compass which is given in the question for the following line segment.
Students can join the arc in last also as per their requirement and step-by-step construction is required here to avoid messiness.
Before constructing the quadrilateral student must keep in mind that in the question, there will \[5\] measurements provided, and in the question, an arc should be made at the point of requirement.
Construction will be easier for the student if the student knows the use of the compass properly to avoid mistakes.
In this question, you have to use a compass.
With the help of a compass, you have to take the value in the compass and mark the value with it and at last, join them.
Complete answer:
Given that,
OL\[ = 7.5\]cm, GL\[ = 6\]cm, GD\[ = 6\]cm, LD\[ = 5\]cm, and OD\[ = 10\]cm
First of all, draw a line segment which is OL\[ = 7.5\]cm
Now, take O as a centre with radius \[10\] cm and draw an arc and join OD.
Now, take L as a centre with radius \[5\] cm and draw an arc, which meets the previous arc at point D and join DL.
Now, Take L as centre with radius \[6\]cm and draw an arc and join GL
Now, Take D as centre with radius \[6\]cm and draw an arc, which meets the previous arc at point G.
Hence, the required quadrilateral GOLD is:
Note:
While constructing the arc student should keep in mind that they take the value in the compass which is given in the question for the following line segment.
Students can join the arc in last also as per their requirement and step-by-step construction is required here to avoid messiness.
Before constructing the quadrilateral student must keep in mind that in the question, there will \[5\] measurements provided, and in the question, an arc should be made at the point of requirement.
Construction will be easier for the student if the student knows the use of the compass properly to avoid mistakes.
Recently Updated Pages
Write any three differences between metals and nonmetals class 10 social science CBSE

Amit standing on a horizontal plane finds a bird flying class 10 maths CBSE

Two circles of radii 5 cm and 3 cm intersect at two class 10 maths CBSE

Solve the following i John and Jivanti together have class 10 maths CBSE

What is the relation between orthocenter circumcentre class 10 maths CBSE

Two plane mirrors are inclined at 70circ A ray incident class 10 physics CBSE

Trending doubts
Explain the Treaty of Vienna of 1815 class 10 social science CBSE

1 GB equals how many MB?

10 examples of evaporation in daily life with explanations

What is the full form of POSCO class 10 social science CBSE

Which is the hottest planet in the Solar system A Earth class 10 social science CBSE

Name any four life processes in living things class 10 biology CBSE

