Consider a conductor of variable cross-section in which current is flowing from section 1 to 2. Then, which of these are true?
A. current passing through both the cross sections is the same.
B. current passing through 1 is less than that through 2
C. drift velocity of electrons at 1 is less than that at 2
D. drift velocity is same at both the cross sections

Hint:

1. Kirchhoff’s Law of current flow: It states that charges are conserved at any junction. It means that at any time, within any cross-section area the same no. of charge leaves the section while the same amount enters into it.
2. Kirchhoff’s law also tells about continuity or steady current flow through the conductor.
3. Drift velocity of the charge depends upon the cross-section of the conductor.

Formula Used:
Current flow through any conductor with cross-section area $A$, no. of electrons $n$ and drift velocity of electrons be ${v_d}$, is given by $I = neA{v_d}$. …… (a)

Complete step by step answer:

Given at position-1 area be ${A_1}$ and at position-2 area be ${A_2}$

Step 1 of 5:

Here, the given conductor is a single one-way conductor.
Hence by using Kirchhoff’s law at any cross section current flowing into the area is equal to current leaving. $ \Rightarrow n$ and $e$ are same at both positions …… (1)

Step 2 of 5:

Using Kirchhoff’s law for single wire with variable thickness we can say A is true.

Step 3 of 5:

Since, current flow is the same for every cross-section area.
$\therefore {I_1} = {I_2}$ for cross section position 1 and 2 …… (2)

Step 4 of 5:

Using equation (1), (2) and (a) we get
${I_1} = {I_2}$
$ \Rightarrow ne{A_1}{v_{1,d}} = ne{A_2}{v_{2,d}}$
$ \Rightarrow {A_1}{v_{1,d}} = {A_2}{v_{2,d}}$ ……. (3)

Step 5 of 5:
By analyzing equation (3), it says the product is constant.
$ \Rightarrow A \propto \dfrac{1}{{{v_d}}}$ ……. (4)
Therefore, C is also true

Correct Answer:
A. current passing through both the cross sections is the same.
C. drift velocity of electrons at 1 is less than that at 2.

Note: Equation (4) is similar to continuity equation of fluid flow. So, we can solve current flow circuits by analogy with fluid flow dynamics if interactions among charges are negligible.