Complete the reaction-
A.
B.
C.
D.
Answer
578.1k+ views
Hint: Here, \[2 - \]ethynylcyclohexan\[ - 1 - \]one is reacted with borane, trihydrofuran, and hydrogen peroxide, there is a formation of one product. And that will react with sodium hydroxide and iodine under heat and there will be the final product. The \[B{H_3}\]reagent is used for hydroboration reaction of alkynes and alkenes. During this reaction, first there is a formation of enol.
Complete answer:
\[2 - \]Oxo cyclohexane\[ - 1 - \]carboxylic acid is not formed by this reaction. Hence, option (A) is incorrect.
There will not be a formation of \[2 - \]Acetylcyclohexan\[ - 1 - \]one. Hence, option (B) is correct.
Here, \[2 - \]ethynylcyclohexan\[ - 1 - \]one is reacted with borane in the presence of trihydrofuran, (THF) and hydrogen peroxide and there is a formation of unstable enol form. The borane is mainly used for the hydroboration of alkynes. Thus, by hydroboration of alkynes, there is a formation of a product called enol which is highly unstable. Therefore, it will react with sodium hydroxide and in the presence of heat, there is a formation of \[2 - \](\[2 - \]oxocyclohexyl) acetaldehyde. Let’s see the reaction,
Hence, option (C) is correct.
There will not be a formation of cyclohexanone as the final product. Hence, the option (D) is incorrect.
Hence, option (C) is correct.
Note:
By the hydroboration of alkynes there is a formation of product called enol and this process is known as tautomerization. And this enol is converted into keto form which is more stable aldehyde. The enol is otherwise called, half alcohol. And the constitutional isomer is aldehyde. This type of reaction is called keto – enol tautomerism.
Complete answer:
\[2 - \]Oxo cyclohexane\[ - 1 - \]carboxylic acid is not formed by this reaction. Hence, option (A) is incorrect.
There will not be a formation of \[2 - \]Acetylcyclohexan\[ - 1 - \]one. Hence, option (B) is correct.
Here, \[2 - \]ethynylcyclohexan\[ - 1 - \]one is reacted with borane in the presence of trihydrofuran, (THF) and hydrogen peroxide and there is a formation of unstable enol form. The borane is mainly used for the hydroboration of alkynes. Thus, by hydroboration of alkynes, there is a formation of a product called enol which is highly unstable. Therefore, it will react with sodium hydroxide and in the presence of heat, there is a formation of \[2 - \](\[2 - \]oxocyclohexyl) acetaldehyde. Let’s see the reaction,
Hence, option (C) is correct.
There will not be a formation of cyclohexanone as the final product. Hence, the option (D) is incorrect.
Hence, option (C) is correct.
Note:
By the hydroboration of alkynes there is a formation of product called enol and this process is known as tautomerization. And this enol is converted into keto form which is more stable aldehyde. The enol is otherwise called, half alcohol. And the constitutional isomer is aldehyde. This type of reaction is called keto – enol tautomerism.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

