Assertion: A frame moving in a circle with a constant speed can never be an inertial frame.
Reason: It has a constant acceleration.
A. Both Assertion and Reason are correct and the reason is the correct explanation for Assertion.
B. Both Assertion and Reason are correct and the reason is not the correct explanation for Assertion.
C. Assertion is correct but Reason is incorrect.
D. Assertion is incorrect but the reason is correct.
Answer
650.4k+ views
Hint: The speed of a body is a scalar quantity that only has a magnitude and there is no specific direction of the body. On the other hand, acceleration is a vector quantity which has some specific velocity as well as the direction.
Complete answer:
When an object is moving in a circular path with the uniform speed as V shown in the diagram,
The speed of a moving body is the scalar quantity. There is no specific direction of such quantities. The linear speed is given by:
$\begin{align}
& \omega =\dfrac{\Delta \theta }{\Delta t} \\
& \Rightarrow v=r\omega \\
\end{align}$
Where,
$\omega $ Is the angular speed
$\Delta \theta $ Is the angle rotation
$t$ Is the time duration
$r$ Is the radius of the circle
$v$ Is the linear speed.
The object moving in the circular path will have a non-inertial frame. This is due to the centripetal acceleration acting on the body. The centripetal acceleration is towards the center. The centripetal force is given by,
${{a}_{c}}=r{{\omega }^{2}}$
Here we can say that the Assertion given in the question is correct.
The acceleration of the body always towards the center of the circle. But its pointing direction always changes according to the position of the object.
Thus the vector of acceleration ( $\vec{a}$ ) will be variable concerning the center of the circle. We can say that the reason is incorrect.
So, the correct answer is “Option C”.
Note:
When an object is moving into a circular path with a uniform speed the force acting on it is known as centripetal force. Concerning Newton’s 3rd law of motion, every acting force has its equal and opposite reaction force. The opposite force acting on the body is known as centrifugal force.
Complete answer:
When an object is moving in a circular path with the uniform speed as V shown in the diagram,
The speed of a moving body is the scalar quantity. There is no specific direction of such quantities. The linear speed is given by:
$\begin{align}
& \omega =\dfrac{\Delta \theta }{\Delta t} \\
& \Rightarrow v=r\omega \\
\end{align}$
Where,
$\omega $ Is the angular speed
$\Delta \theta $ Is the angle rotation
$t$ Is the time duration
$r$ Is the radius of the circle
$v$ Is the linear speed.
The object moving in the circular path will have a non-inertial frame. This is due to the centripetal acceleration acting on the body. The centripetal acceleration is towards the center. The centripetal force is given by,
${{a}_{c}}=r{{\omega }^{2}}$
Here we can say that the Assertion given in the question is correct.
The acceleration of the body always towards the center of the circle. But its pointing direction always changes according to the position of the object.
Thus the vector of acceleration ( $\vec{a}$ ) will be variable concerning the center of the circle. We can say that the reason is incorrect.
So, the correct answer is “Option C”.
Note:
When an object is moving into a circular path with a uniform speed the force acting on it is known as centripetal force. Concerning Newton’s 3rd law of motion, every acting force has its equal and opposite reaction force. The opposite force acting on the body is known as centrifugal force.
Recently Updated Pages
Difference Between Prokaryotic Cells and Eukaryotic Cells

If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

