An element having configuration \[1{s^2}2{s^2}2{p^6}3{s^2}3{p^6}4{s^1}\] will form-

Hint: The given element should be occupied in the group one. Because, here the valence electrons are entered in the s – orbital. Therefore, the given element is an alkali metal element. Because, the first group elements are known as alkali metal elements. The alkali metals are sodium, potassium, rubidium, cesium and francium. These metals are highly reactive and have low ionization energy, low electronegativity, low melting points etc. These elements are not occupied as freely in nature.

Complete answer:
The given element is an alkali metal element which is potassium. And the element will form metallic oxides.
When the oxygen is reacted with metals there is a formation of metal oxides. And these are mainly divided into three. Acidic oxide, basic oxide and neutral oxide. In the case of acidic oxides, there is a formation of acid when the metal oxide is reacted with water. If it gives a base, then the oxide is basic oxide. For neutral oxide, it will not give any acid and bases.
Here, the given compound gives a basic oxide. Because, when potassium metal oxide reacts with water, there is a formation of potassium hydroxide, which is a base. Hence, the metal oxide is a basic oxide. Let’s see the reaction.
\[{K_2}O + {H_2}O \to 2KOH\]

Note:
We need to remember that the element having configuration \[1{s^2}2{s^2}2{p^6}3{s^2}3{p^6}4{s^1}\]will form a basic oxide. The basic oxides are ionic in nature. When the basic oxide is reacted with water, there is a formation of metal hydroxides which is basic in nature. For example, sodium oxide, potassium oxide, etc. Sodium oxide is the most basic oxide. In the case of acidic oxide, which gives acidic hydroxides.