An element A is tetravalent and another element B is divalent. The formula of the compound formed by the combination of these elements is:
A. \[{A_2}B\]
B. \[AB\]
C. \[A{B_2}\]
D. \[{A_2}{B_3}\]
Answer
650.4k+ views
Hint: The molecular formula of a compound represents the atoms and the number of atoms present in the compound. The number of the atoms in the compound are written in the form of suffix. A structural formula of a compound represents the structure of a particular compound.
Complete step by step answer:
We are given that an element A is tetravalent, hence its oxidation number can be \[{{\text{A}}^{{\text{ + 4}}}}\]
Also, it is also given that element B is divalent hence its oxidation number can be \[{{\text{B}}^{{\text{2}} - }}\].
Therefore, we give the formula of the compound by cross method as,
So, the formula of the compound will be \[{{\text{A}}_{\text{2}}}{{\text{B}}_{\text{4}}}\]or \[{\text{A}}{{\text{B}}_2}\].
So, the correct answer is Option C .
Note:
In chemical compounds, the elements are present in a fixed ratio by mass. This was given by Joseph Proust. This is the “law of constant proportions''. This “law of constant proportions” is also termed as the law of definite proportions or as the Proust’s law. For example, pure water contains oxygen and hydrogen in a fixed ratio of 1:8. Water contains 0.88 grams of oxygen and 0.11 grams of hydrogen
Students may get confused between formula units and molecular formulas. By formula unit we represent the ratio of the ions which is present in a compound. The molecular formula of a compound represents the atoms and the number of atoms present in the compound. The number of the atoms in the compound are written in the form of suffix.
Complete step by step answer:
We are given that an element A is tetravalent, hence its oxidation number can be \[{{\text{A}}^{{\text{ + 4}}}}\]
Also, it is also given that element B is divalent hence its oxidation number can be \[{{\text{B}}^{{\text{2}} - }}\].
Therefore, we give the formula of the compound by cross method as,
So, the formula of the compound will be \[{{\text{A}}_{\text{2}}}{{\text{B}}_{\text{4}}}\]or \[{\text{A}}{{\text{B}}_2}\].
So, the correct answer is Option C .
Note:
In chemical compounds, the elements are present in a fixed ratio by mass. This was given by Joseph Proust. This is the “law of constant proportions''. This “law of constant proportions” is also termed as the law of definite proportions or as the Proust’s law. For example, pure water contains oxygen and hydrogen in a fixed ratio of 1:8. Water contains 0.88 grams of oxygen and 0.11 grams of hydrogen
Students may get confused between formula units and molecular formulas. By formula unit we represent the ratio of the ions which is present in a compound. The molecular formula of a compound represents the atoms and the number of atoms present in the compound. The number of the atoms in the compound are written in the form of suffix.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

