A triangle has a base measuring 15 cm and a height of 16 cm. Calculate its area.

Hint: We will calculate the area of the required triangle using the formula $\dfrac{1}{2} \times b \times h$, where $b$ is the base of the triangle and $h$ is the perpendicular height of the triangle. We will substitute the given values of base and height of the triangle and then simplify the expression to find the area of the triangle. Also, do not forget to mention the units of area of the triangle.

Complete step-by-step answer:
We are given that the base of the triangle is 15 cm and the height of the triangle is 16 cm.
We know that the area of the triangle is given as $\dfrac{1}{2} \times b \times h$, where $b$ is the base of the triangle and $h$ is the perpendicular height of the triangle.

We will now substitute the value of the base of the triangle as 15 cm and the value of height of triangle as 16 cm.
Then, area of the respective triangle is calculated as,
$A = \dfrac{1}{2} \times 15 \times 16$
On simplifying the above expression, we will get,
$
  A = \dfrac{1}{2} \times 240 \\
   \Rightarrow A = 120c{m^2} \\
$
Hence, the area of the triangle is $120c{m^2}$

Note: Area of the figure is the space covered by the figure. The height mentioned in the question represents a perpendicular distance from the base of the triangle to the opposite vertex of the triangle. Also, the area of any figure is always measured in square units.