A dice is thrown once. The probability of getting a number greater than 3 is ______.
(a)\[\dfrac{1}{2}\]
(b)\[\dfrac{1}{3}\]
(c)\[\dfrac{2}{3}\]
(d)0

Hint: Find the number of sides which has a number greater than 3 in a die. Thus the probability will be the number of these sides by the total number of sides of the die.

Complete step-by-step answer:
We know that the probability of all the events that can happen is 1.
We know that a dice has six sides, which are numbered as 1, 2, 3, 4, 5, 6.
Now by observing these numbers, we can say that these are 3 numbers which are greater than 3, which are 4, 5, 6.
Thus there are 3 sides of the die, which shows numbers greater than three out of 6 sides of the die.
There we can find the probability as the number of sides that have 4, 5, 6 values by the total number of sides of the dice.
\[\therefore \] Probability of getting a number greater than 3
= Number of sides which as number greater than 3 / Total number of sides of the dice
\[=\dfrac{3}{6}=\dfrac{1}{2}\]
Thus we got the probability of getting a number greater than 3 is \[\dfrac{1}{2}\].
Thus we got the required probability.
\[\therefore \] Option (a) is the correct answer.

Note: If we were to find the probability of number less than 3, including 3 then the probability will also be \[\dfrac{1}{2}\] i.e. the numbers will be 1,2 and 3. The number of sides with these numbers will be 3. Thus probability = number of sides by total number of sides of the dice \[=\dfrac{3}{6}=\dfrac{1}{2}\].