A Carnot engine operates with a source at $500\;{\text{K}}$ and sinks at $375\;{\text{K}}$. If the engine takes $600\;{\text{kcal}}$ of heat in one cycle, the heat rejected to sink per cycle is
A. $250\;{\text{kcal}}$
B. $350\;{\text{kcal}}$
C. $450\;{\text{kcal}}$
D. $550\;{\text{kcal}}$
Answer
650.1k+ views
Hint:The above problem is based on the Carnot cycle. The efficiency of the Carnot cycle is equal to the heat output to heat input. The efficiency can be expressed in terms of temperature also. The heat rejected by the sink will be equal to the difference between heat input of the cycle and heat used in the cycle.
Complete step by step answer:
Given: The temperature of the source is ${T_1} = 500\;{\text{K}}$
The temperature of the sink is ${T_2} = 375\;{\text{K}}$
The heat taken by the engine is ${Q_1} = 600\;{\text{kcal}}$
The expression to calculate the efficiency of the Carnot engine is,
$\eta = 1 - \dfrac{{{T_2}}}{{{T_1}}}$
Substitute $500\;{\text{K}}$for ${T_1}$ and $375\;{\text{K}}$for ${T_2}$ in the above expression to find the efficiency of the Carnot engine.
$\eta = 1 - \dfrac{{375\;{\text{K}}}}{{500\;{\text{K}}}}$
$\Rightarrow\eta = 0.25$
The expression to calculate the heat rejected to sink per cycle is,
$Q = \left( {1 - \eta } \right){Q_1}$
Substitute 0.25 for $\eta $ and $600\;{\text{kcal}}$for ${Q_1}$ to find the heat rejected to sink per cycle.
$Q = \left( {1 - 0.25} \right)\left( {600\;{\text{kcal}}} \right)$
$\therefore Q = 450\;{\text{kcal}}$
Thus, the heat rejected to sink per cycle is $450\;{\text{kcal}}$ and the option (C) is the correct answer.
Additional Information:
The Carnot cycle is the heat cycle that consists of two isothermal processes and two isobaric processes. This heat cycle is the standard cycle for the thermodynamic processes. All thermodynamic devices are designed on the basis of the Carnot efficiency of the process.
Note:Always remember the both formula to find the efficiency of the Carnot cycle. One method to find the efficiency is by the ratio of heat output to heat input and another method is on the basis of the temperature of the source and sink.
Complete step by step answer:
Given: The temperature of the source is ${T_1} = 500\;{\text{K}}$
The temperature of the sink is ${T_2} = 375\;{\text{K}}$
The heat taken by the engine is ${Q_1} = 600\;{\text{kcal}}$
The expression to calculate the efficiency of the Carnot engine is,
$\eta = 1 - \dfrac{{{T_2}}}{{{T_1}}}$
Substitute $500\;{\text{K}}$for ${T_1}$ and $375\;{\text{K}}$for ${T_2}$ in the above expression to find the efficiency of the Carnot engine.
$\eta = 1 - \dfrac{{375\;{\text{K}}}}{{500\;{\text{K}}}}$
$\Rightarrow\eta = 0.25$
The expression to calculate the heat rejected to sink per cycle is,
$Q = \left( {1 - \eta } \right){Q_1}$
Substitute 0.25 for $\eta $ and $600\;{\text{kcal}}$for ${Q_1}$ to find the heat rejected to sink per cycle.
$Q = \left( {1 - 0.25} \right)\left( {600\;{\text{kcal}}} \right)$
$\therefore Q = 450\;{\text{kcal}}$
Thus, the heat rejected to sink per cycle is $450\;{\text{kcal}}$ and the option (C) is the correct answer.
Additional Information:
The Carnot cycle is the heat cycle that consists of two isothermal processes and two isobaric processes. This heat cycle is the standard cycle for the thermodynamic processes. All thermodynamic devices are designed on the basis of the Carnot efficiency of the process.
Note:Always remember the both formula to find the efficiency of the Carnot cycle. One method to find the efficiency is by the ratio of heat output to heat input and another method is on the basis of the temperature of the source and sink.
Recently Updated Pages
Write structures of the following compounds i 2 Chloro3methylpentane class 11 chemistry CBSE

What is BLO What is the full form of BLO class 8 social science CBSE

Explain the Treaty of Vienna of 1815 class 10 social science CBSE

A Paragraph on Pollution in about 100-150 Words

XIX+XXX A 49 B 51 C 55 D 44 class 5 maths CBSE

If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

What do you mean by retardation What is its SI uni class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Difference between physical and chemical change class 11 chemistry CBSE

