How far will a car travel in 25 min at 12 m/s?
Answer
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Hint: The magnitude of the rate of change of an item's position with time or the magnitude of change of its position per unit of time is the speed (often referred to as v) of an item in daily use and in kinematics; it is therefore a scalar number. The average speed of an object in a given time interval is the item's distance travelled divided by the period's duration; the instantaneous speed is the average speed's limit as the interval's length approaches zero.
$ {\text{Speed = }}\dfrac{{{\text{Distance}}}}{{{\text{time}}}} $
Complete answer:
The parameters of speed are distance divided by time. The metre per second (m/s) is the SI unit of speed, while the kilometre per hour (km/h) or miles per hour (in the US and the UK) is the most used measure of speed in everyday use (mph). The knot is extensively used in aviation and maritime transport.
Given : In 25 minutes, an automobile drives at a speed of 12 m/s.
When the automobile moves at 12 m/s for 25 minutes, we must calculate the distance.
We use $ {\text{Speed = }}\dfrac{{{\text{Distance}}}}{{{\text{time}}}} $
$ \therefore Distance{\text{ }} = {\text{ }}Speed{\text{ }} \times {\text{ }}Time $
Putting the values we get
$ Distance{\text{ }} = {\text{ }}12{\text{ m/s }} \times 25\,\min \, $
Converting minute into second we get
$ Distance{\text{ }} = {\text{ }}12{\text{ }}m/s{\text{ }} \times {\text{ }}25{\text{ }} \times {\text{ }}60{\text{ }}sec $
Finally we get
$ Distance{\text{ }} = {\text{ }}18000{\text{ }}m $
We can also write distance in km
$ Distance{\text{ }} = 18{\text{ }}km $
Hence the car will travel 18 km in 25 min at 12 m/s.
Note:
The distance travelled per unit of time is known as linear speed, but the linear speed of anything travelling in a circular route is known as tangential speed (or tangential velocity). In one complete rotation, a point on the outside edge of a merry-go-round or turntable travels a larger distance than a point closer to the centre. Linear speed is larger on the outside edge of a spinning item than it is closer to the axis because you may go a longer distance in the same amount of time. Because the direction of motion is tangent to the circumference of the circle, this speed along a circular path is known as tangential speed.
$ {\text{Speed = }}\dfrac{{{\text{Distance}}}}{{{\text{time}}}} $
Complete answer:
The parameters of speed are distance divided by time. The metre per second (m/s) is the SI unit of speed, while the kilometre per hour (km/h) or miles per hour (in the US and the UK) is the most used measure of speed in everyday use (mph). The knot is extensively used in aviation and maritime transport.
Given : In 25 minutes, an automobile drives at a speed of 12 m/s.
When the automobile moves at 12 m/s for 25 minutes, we must calculate the distance.
We use $ {\text{Speed = }}\dfrac{{{\text{Distance}}}}{{{\text{time}}}} $
$ \therefore Distance{\text{ }} = {\text{ }}Speed{\text{ }} \times {\text{ }}Time $
Putting the values we get
$ Distance{\text{ }} = {\text{ }}12{\text{ m/s }} \times 25\,\min \, $
Converting minute into second we get
$ Distance{\text{ }} = {\text{ }}12{\text{ }}m/s{\text{ }} \times {\text{ }}25{\text{ }} \times {\text{ }}60{\text{ }}sec $
Finally we get
$ Distance{\text{ }} = {\text{ }}18000{\text{ }}m $
We can also write distance in km
$ Distance{\text{ }} = 18{\text{ }}km $
Hence the car will travel 18 km in 25 min at 12 m/s.
Note:
The distance travelled per unit of time is known as linear speed, but the linear speed of anything travelling in a circular route is known as tangential speed (or tangential velocity). In one complete rotation, a point on the outside edge of a merry-go-round or turntable travels a larger distance than a point closer to the centre. Linear speed is larger on the outside edge of a spinning item than it is closer to the axis because you may go a longer distance in the same amount of time. Because the direction of motion is tangent to the circumference of the circle, this speed along a circular path is known as tangential speed.
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