A & B working together can complete a task in 8 days, B & C can do it in 16 days. A worked at it for 5 days & B worked at it for 1 5 days & B worked at it for 6 days C alone finished the remaining work in 16 days. How many days would C take to complete the same work alone?
Answer
640.5k+ views
Hint:
We convert the work done into unit work then solve the equations and we will find the work done by C working alone
Formula used: $\dfrac{1}{\text{A}}+\dfrac{1}{\text{B}}+\dfrac{1}{\text{C}}=\dfrac{1}{\text{tag}}$
i.e. work done by A in one day$+$ work done by B in one day$+$ work done by A, B, C working together in one day.
Complete step by step solution:
Let us assume that total work=x
A & B can complete the work in 8 days
$\therefore $ \[\left( \text{A}+\text{B} \right)\times 8=\text{x}\]
$\left( \text{A}+\text{B} \right)=\dfrac{\text{x}}{8}$ …… (2)
B & C can complete the work in 16 days
$\begin{align}
& \left( \text{B}+\text{C} \right)\times 16=\text{x} \\
& \left( \text{B}+\text{C} \right)=\dfrac{\text{x}}{16}......(2) \\
\end{align}$
If A works for 5 days then work done by A$=5\times \text{A}$
=5A
If B works for 6 days then work done by B$=6\times \text{B}$
=6B
If C works for 16 days then work done by C =\[16\times \text{C}\]
=16C
Then according to condition
5A$+$6B$+$16C=x
$\left( 5\text{A}+5\text{B} \right)+\left( \text{B}+\text{C} \right)+15\text{ C=x}$
From (1) & (2) we get
$\left( 5\text{A}+5\text{B} \right)+\left( \text{B}+\text{C} \right)+15\text{ C=x}$
$\begin{align}
& 5\left( \dfrac{\text{x}}{8} \right)+\dfrac{\text{x}}{16}+15\text{ C=x} \\
& \dfrac{5\text{x}}{8}+\dfrac{\text{x}}{16}+15\text{ C=x} \\
& \text{15 C=x}-\dfrac{\text{5x}}{8}-\dfrac{\text{x}}{16} \\
\end{align}$
$\begin{align}
& 15\text{ C}=\dfrac{16\text{x}-10\text{x}-\text{x}}{16} \\
& 15\text{ C}=\dfrac{5\text{x}}{16} \\
& \text{C}=\dfrac{5\text{x}}{16\times 15} \\
& \text{ }=\dfrac{\text{x}}{48} \\
\end{align}$
Therefore C alone can complete the work in 48 days.
Note:
Additional information: We can assume the total work as 1. Then solve the question in the similar manner.
Note: We also convert the work done in one day to work so it’s always easy to solve the problem at work.
We convert the work done into unit work then solve the equations and we will find the work done by C working alone
Formula used: $\dfrac{1}{\text{A}}+\dfrac{1}{\text{B}}+\dfrac{1}{\text{C}}=\dfrac{1}{\text{tag}}$
i.e. work done by A in one day$+$ work done by B in one day$+$ work done by A, B, C working together in one day.
Complete step by step solution:
Let us assume that total work=x
A & B can complete the work in 8 days
$\therefore $ \[\left( \text{A}+\text{B} \right)\times 8=\text{x}\]
$\left( \text{A}+\text{B} \right)=\dfrac{\text{x}}{8}$ …… (2)
B & C can complete the work in 16 days
$\begin{align}
& \left( \text{B}+\text{C} \right)\times 16=\text{x} \\
& \left( \text{B}+\text{C} \right)=\dfrac{\text{x}}{16}......(2) \\
\end{align}$
If A works for 5 days then work done by A$=5\times \text{A}$
=5A
If B works for 6 days then work done by B$=6\times \text{B}$
=6B
If C works for 16 days then work done by C =\[16\times \text{C}\]
=16C
Then according to condition
5A$+$6B$+$16C=x
$\left( 5\text{A}+5\text{B} \right)+\left( \text{B}+\text{C} \right)+15\text{ C=x}$
From (1) & (2) we get
$\left( 5\text{A}+5\text{B} \right)+\left( \text{B}+\text{C} \right)+15\text{ C=x}$
$\begin{align}
& 5\left( \dfrac{\text{x}}{8} \right)+\dfrac{\text{x}}{16}+15\text{ C=x} \\
& \dfrac{5\text{x}}{8}+\dfrac{\text{x}}{16}+15\text{ C=x} \\
& \text{15 C=x}-\dfrac{\text{5x}}{8}-\dfrac{\text{x}}{16} \\
\end{align}$
$\begin{align}
& 15\text{ C}=\dfrac{16\text{x}-10\text{x}-\text{x}}{16} \\
& 15\text{ C}=\dfrac{5\text{x}}{16} \\
& \text{C}=\dfrac{5\text{x}}{16\times 15} \\
& \text{ }=\dfrac{\text{x}}{48} \\
\end{align}$
Therefore C alone can complete the work in 48 days.
Note:
Additional information: We can assume the total work as 1. Then solve the question in the similar manner.
Note: We also convert the work done in one day to work so it’s always easy to solve the problem at work.
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