The letter below represents a $3 \lambda $ difference in path length?

A) Position A
B) Position B
C) Position C
D) Position D
E) Position E
Answer
300.3k+ views
Hint: The path difference in the center is zero. The intensity falls to zero as we move towards right or left and reaches the minimum and then there is the region of minimum. From the centre, the path difference at every maxima becomes $\lambda $.
Complete step by step answer:
The difference between the path traversed by the waves is known as path difference. It is represented by $\Delta x$ whose unit is metre $\left( m \right)$.The formula for calculating the path difference is –
$\Delta x = \dfrac{\lambda }{{2\pi }}\Delta \phi $
where, $\Delta \phi $ is the phase difference.
From the figure above in the question, in the centre the path difference is zero. The path difference can be found by the variation of intensity. When we move towards right or left then the intensity falls to zero and we reach the minimum. So, the region we get is the region of minima. After this we get the region of high intensity and the distance between two peaks have the path difference of length $\lambda $ at every maxima. Hence, at the centre the path difference is zero so, the position E represents the path difference $3\lambda $.
Hence, the correct option is (E).
Note: Two waves, each emitted by the same source, can reach a point by travelling different paths. When this happens, Interference can occur.
The path difference is of two types:
1) Optical path difference
2) Geometrical path difference
Complete step by step answer:
The difference between the path traversed by the waves is known as path difference. It is represented by $\Delta x$ whose unit is metre $\left( m \right)$.The formula for calculating the path difference is –
$\Delta x = \dfrac{\lambda }{{2\pi }}\Delta \phi $
where, $\Delta \phi $ is the phase difference.
From the figure above in the question, in the centre the path difference is zero. The path difference can be found by the variation of intensity. When we move towards right or left then the intensity falls to zero and we reach the minimum. So, the region we get is the region of minima. After this we get the region of high intensity and the distance between two peaks have the path difference of length $\lambda $ at every maxima. Hence, at the centre the path difference is zero so, the position E represents the path difference $3\lambda $.
Hence, the correct option is (E).
Note: Two waves, each emitted by the same source, can reach a point by travelling different paths. When this happens, Interference can occur.
The path difference is of two types:
1) Optical path difference
2) Geometrical path difference
Recently Updated Pages
If the magnetizing field on a ferromagnetic material class 12 physics JEE_Main

A point charge is placed at the corner of a cube The class 12 physics JEE_Main

What changes occur if the monochromatic light used class 12 physics JEE_Main

The unit of specific conductance is A Ohm B Ohmmetre class 12 physics JEE_Main

Which lens is used in magnifying glass A Concave lens class 12 physics JEE_Main

Sir C V Raman won the Nobel Prize in which year A 1928 class 12 physics JEE_Main

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

Understanding the Electric Field of a Uniformly Charged Ring

Electron Gain Enthalpy and Electron Affinity Explained

Derivation of Equation of Trajectory Explained for Students

Understanding Atomic Structure for Beginners

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
CBSE Class 12 Physics Question Paper 2026: Download SET-wise PDF with Answer Key & Analysis

JEE Advanced Percentile vs Marks 2026: JEE Main Cutoff, AIR & IIT Admission Guide

Understanding Uniform Acceleration in Physics

Hybridisation in Chemistry – Concept, Types & Applications

Effective Nuclear Charge for JEE

Understanding the Angle of Deviation in a Prism

