The equivalent resistance between X and Y will be

A) 4 ohm
B) 4.5 ohm
C) 2 ohm
D) 20 ohm.
Answer
299.4k+ views
Hint: Resistors are said to be in parallel when their two terminals connect to the same node. On the other hand, resistors are said to be in series when they are connected head-to-tail and there is no other wire branching off from the nodes between components. For example, in the above circuit, the resistors 7 ohm and 2 ohm are connected parallel.
Complete step by step solution:
Step 1: first we will calculate the equivalent resistance $R'$ of the 7ohm and 2 ohm. Express the formula for the equivalent resistance when two resistors are connected parallel.
$\therefore \dfrac{1}{{R'}} = \dfrac{1}{{{R_1}}} + \dfrac{1}{{{R_2}}}$ , where $R'$ is the equivalent resistor of the 7 ohm and 2 ohm.
Step 2: Substitute the values for ${R_1}$ and ${R_2}$
$\therefore \dfrac{1}{{R'}} = \dfrac{1}{7} + \dfrac{1}{2}$
$ \Rightarrow \dfrac{1}{{R'}} = \dfrac{9}{{14}}$
Step 3: Take the reciprocal on both sides
\[\therefore R' = \dfrac{{14}}{9}\]
Step 4: Now similarly calculate the equivalent resistance $R''$ of 5 ohm and 6 ohm which is also parallel.
$\therefore \dfrac{1}{{R''}} = \dfrac{1}{{{R_1}}} + \dfrac{1}{{{R_2}}}$
Step 5: Substitute the values for ${R_1}$ and ${R_2}$
$\therefore \dfrac{1}{{R''}} = \dfrac{1}{5} + \dfrac{1}{6}$
$ \Rightarrow \dfrac{1}{{R''}} = \dfrac{{11}}{{30}}$
Step 6: Now our circuit will be

Now clearly you can see that there are two resistors in our circuit and both are connected in a series. Express the formula for the equivalent resistance of the two resistors connected in series.
$\therefore {R_{equ}} = {R_1} + {R_2}$
Step 7: Now substitute the values $\dfrac{{14}}{9}$ for ${R_1}$ and $\dfrac{{11}}{{30}}$ for ${R_2}$
$\therefore {R_{equ}} = \dfrac{{14}}{9} + \dfrac{{11}}{{30}}$
$ \Rightarrow {R_{equ}} \simeq 2$ ohm
Hence the correct option is Option C.
Note: While calculating equivalent resistance in a circuit always remember that the resistors connected parallel should be added first. After adding all parallel resistors the entire circuit will become simple where all the remaining resistors will be connected in series. Resistors connected in series are easier to find equivalent resistance.
Complete step by step solution:
Step 1: first we will calculate the equivalent resistance $R'$ of the 7ohm and 2 ohm. Express the formula for the equivalent resistance when two resistors are connected parallel.
$\therefore \dfrac{1}{{R'}} = \dfrac{1}{{{R_1}}} + \dfrac{1}{{{R_2}}}$ , where $R'$ is the equivalent resistor of the 7 ohm and 2 ohm.
Step 2: Substitute the values for ${R_1}$ and ${R_2}$
$\therefore \dfrac{1}{{R'}} = \dfrac{1}{7} + \dfrac{1}{2}$
$ \Rightarrow \dfrac{1}{{R'}} = \dfrac{9}{{14}}$
Step 3: Take the reciprocal on both sides
\[\therefore R' = \dfrac{{14}}{9}\]
Step 4: Now similarly calculate the equivalent resistance $R''$ of 5 ohm and 6 ohm which is also parallel.
$\therefore \dfrac{1}{{R''}} = \dfrac{1}{{{R_1}}} + \dfrac{1}{{{R_2}}}$
Step 5: Substitute the values for ${R_1}$ and ${R_2}$
$\therefore \dfrac{1}{{R''}} = \dfrac{1}{5} + \dfrac{1}{6}$
$ \Rightarrow \dfrac{1}{{R''}} = \dfrac{{11}}{{30}}$
Step 6: Now our circuit will be

Now clearly you can see that there are two resistors in our circuit and both are connected in a series. Express the formula for the equivalent resistance of the two resistors connected in series.
$\therefore {R_{equ}} = {R_1} + {R_2}$
Step 7: Now substitute the values $\dfrac{{14}}{9}$ for ${R_1}$ and $\dfrac{{11}}{{30}}$ for ${R_2}$
$\therefore {R_{equ}} = \dfrac{{14}}{9} + \dfrac{{11}}{{30}}$
$ \Rightarrow {R_{equ}} \simeq 2$ ohm
Hence the correct option is Option C.
Note: While calculating equivalent resistance in a circuit always remember that the resistors connected parallel should be added first. After adding all parallel resistors the entire circuit will become simple where all the remaining resistors will be connected in series. Resistors connected in series are easier to find equivalent resistance.
Recently Updated Pages
If the magnetizing field on a ferromagnetic material class 12 physics JEE_Main

A point charge is placed at the corner of a cube The class 12 physics JEE_Main

What changes occur if the monochromatic light used class 12 physics JEE_Main

The unit of specific conductance is A Ohm B Ohmmetre class 12 physics JEE_Main

Which lens is used in magnifying glass A Concave lens class 12 physics JEE_Main

Sir C V Raman won the Nobel Prize in which year A 1928 class 12 physics JEE_Main

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

Understanding the Electric Field of a Uniformly Charged Ring

Understanding Atomic Structure for Beginners

Electron Gain Enthalpy and Electron Affinity Explained

Derivation of Equation of Trajectory Explained for Students

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
CBSE Class 12 Physics Question Paper 2026: Download SET-wise PDF with Answer Key & Analysis

JEE Advanced Percentile vs Marks 2026: JEE Main Cutoff, AIR & IIT Admission Guide

What Are Current and Potential Difference in Electricity?

Understanding Uniform Acceleration in Physics

Hybridisation in Chemistry – Concept, Types & Applications

Understanding Geostationary and Geosynchronous Satellites

