The displacement of a particle in simple harmonic motion in one time period is:
A. A
B. 2A
C. 4A
D. Zero
Answer
299.7k+ views
Hint:In this question we are given a particle which is in simple harmonic motion and we are asked to find the total displacement of the same particle from the given four options, we will use the formula for the initial position of the particle and then will find the position of the same particle after one time period and then will find the net displacement.
Formula used:
The formula for initial position of the particle in a simple harmonic motion is given as,
\[y = A\sin \left( {\omega t + \phi } \right)\]
Here in the equation,
\[\left( {\omega t + \phi } \right)\] is the phase of the motion, \[\phi \] is the initial phase of the motion of particles and \[A\] is the amplitude.
Complete step by step solution:
We can write this equation simple harmonic motion as
\[y = A\sin \left( {\dfrac{{2\pi }}{T}t + \phi } \right)\]
Since, \[\omega = \dfrac{{2\pi }}{T}\]..... (the time period of a particle is inversely proportional to frequency)
Now, let us consider the position of the same particle which is in simple harmonic motion after one time period, we have
\[{y_T} = A\sin \left( {\dfrac{{2\pi }}{T}\left( {t + T} \right) + \phi } \right)\]
Further solving this equation, we have
\[{y_T} = A\sin \left( {\dfrac{{2\pi }}{T}t + 2\pi + \phi } \right)\]
Now, the net displacement of the particle in simple harmonic motion in one time period will be,
\[d = {y_t} - y\\ \Rightarrow d = A\sin \left( {\dfrac{{2\pi }}{T}t + \phi } \right)\, - A\sin \left( {\dfrac{{2\pi }}{T}t + \phi } \right)\,\\ \therefore d = 0\]
Hence we can say that the net displacement of the particle is zero.
Therefore, option D is correct.
Note:In one time period the particle in harmonic motion comes to the same point from where it started, in this case, the initial position of the particle becomes the same as the final position so the displacement of the particle remains zero. The displacement of a particle or wave is measured from the equilibrium position of the particle.
Formula used:
The formula for initial position of the particle in a simple harmonic motion is given as,
\[y = A\sin \left( {\omega t + \phi } \right)\]
Here in the equation,
\[\left( {\omega t + \phi } \right)\] is the phase of the motion, \[\phi \] is the initial phase of the motion of particles and \[A\] is the amplitude.
Complete step by step solution:
We can write this equation simple harmonic motion as
\[y = A\sin \left( {\dfrac{{2\pi }}{T}t + \phi } \right)\]
Since, \[\omega = \dfrac{{2\pi }}{T}\]..... (the time period of a particle is inversely proportional to frequency)
Now, let us consider the position of the same particle which is in simple harmonic motion after one time period, we have
\[{y_T} = A\sin \left( {\dfrac{{2\pi }}{T}\left( {t + T} \right) + \phi } \right)\]
Further solving this equation, we have
\[{y_T} = A\sin \left( {\dfrac{{2\pi }}{T}t + 2\pi + \phi } \right)\]
Now, the net displacement of the particle in simple harmonic motion in one time period will be,
\[d = {y_t} - y\\ \Rightarrow d = A\sin \left( {\dfrac{{2\pi }}{T}t + \phi } \right)\, - A\sin \left( {\dfrac{{2\pi }}{T}t + \phi } \right)\,\\ \therefore d = 0\]
Hence we can say that the net displacement of the particle is zero.
Therefore, option D is correct.
Note:In one time period the particle in harmonic motion comes to the same point from where it started, in this case, the initial position of the particle becomes the same as the final position so the displacement of the particle remains zero. The displacement of a particle or wave is measured from the equilibrium position of the particle.
Recently Updated Pages
Four persons A B C and D initially at the corners of class 11 physics JEE_Main

What is the difference between Conduction and conv class 11 physics JEE_Main

Moment of inertia of solid sphere about its diameter class 11 physics JEE_Main

If a piece of ice floating on the surface of water class 11 physics JEE_Main

At what temperature speed of sound in air will be doubled class 11 physics JEE_Main

A closed organ pipe and an open organ pipe are tuned class 11 physics JEE_Main

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

Understanding the Electric Field of a Uniformly Charged Ring

Electron Gain Enthalpy and Electron Affinity Explained

Derivation of Equation of Trajectory Explained for Students

Understanding Atomic Structure for Beginners

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
CBSE Notes Class 11 Physics Chapter 1 - Units And Measurements - 2026-27 PDF Download (Login Required)

NCERT Solutions For Class 11 Physics Chapter 1 Units And Measurements - 2026-27 Free PDF Download (Login Required)

NCERT Solutions For Class 11 Physics Chapter 2 Motion In A Straight Line - 2026-27 Free PDF Download (Login Required)

Important Questions For Class 11 Physics Chapter 1 Units and Measurement - 2026-27 Free PDF Download (Sign-in Required)

CBSE Notes Class 11 Physics Chapter 2 - Motion in a Straight Line - 2026-27 PDF Download (Login Required)

NCERT Solutions For Class 11 Physics Chapter 3 Motion In A Plane - 2026-27 Free PDF Download (Sign-in Required)

