In a mixed grouping of identical cells, $5$ rows are connected in parallel by each row contains $10$ cells. This combination sends a current ${{i}}$ through an external resistance of ${{20 \Omega }}$. If the emf and internal resistance of each cell is ${{1}}{{.5 V}}$ and $1{{ }}\Omega $, respectively then the value of ${{i}}$ is:
A) 0.14
B) 0.25
C) 0.75
D) 0.68
Answer
298.5k+ views
Hint: When n cells of same emf are connected in series combination the value of current, ${{I = }}\dfrac{{{E}}}{{{r}}}$. When n cells of same emf are connected in parallel combination the value of current, ${{I = }}\dfrac{{{E}}}{{{{R + }}\dfrac{{{r}}}{{{n}}}}}$. Parallel combination of mix grouping of cells, the value of current is given by
${{I = }}\dfrac{{{{nE}}}}{{{{R + }}\dfrac{{{{nr}}}}{{{m}}}}}$.
Complete step by step solution:
Given: The number of cells in a row, ${{n = 10}}$
The number of rows, ${{m = 5}}$
Emf of each cell, ${{E = 1}}{{.5 V}}$
Internal resistance of each cell, ${{r = 1 \Omega }}$
Electric current is defined as the rate of flow of charge through a conductor in any cross sectional area in a definite direction. SI unit of electric current is ampere represented by A.
Emf is defined as the maximum potential difference between the terminal of the cell when no current is drawn from the cell or the circuit is open. SI unit of emf is voltage represented by V.
Internal resistance is the resistance offered by the electrolyte of the cells to the flow of charge. SI unit of internal resistance is ohms represented by $\Omega $.
Formula for current in mix grouping of cells is given by
$\Rightarrow {{i = }}\dfrac{{{{nE}}}}{{{{R + }}\dfrac{{{{nr}}}}{{{m}}}}}...{{(i)}}$
Where total resistance ${{ = R + }}\dfrac{{{{nr}}}}{{{m}}}$
Now substituting the given values in formula (i), we get
$
\Rightarrow {{i = }}\dfrac{{{{10 \times 15}}}}{{{{20 + }}\dfrac{{{{10 \times 1}}}}{{{5}}}}} \\
\Rightarrow {{i = }}\dfrac{{{{55}}}}{{{{22}}}} \\
\therefore {{i = 0}}{{.68 A}} $
Note: When the cells are joined in a mix group, then to get the maximum current the load resistance must be equal to the internal resistance of the cell. The value of emf of the cells connected in parallel combination remains the same i.e. ${{{E}}_{{{eqv}}}}{{ = E}}$.
For example: If 2 cells are connected in parallel or 100 cells connected in parallel combination the value of equivalent emf remains the same in both the cases.
${{I = }}\dfrac{{{{nE}}}}{{{{R + }}\dfrac{{{{nr}}}}{{{m}}}}}$.
Complete step by step solution:
Given: The number of cells in a row, ${{n = 10}}$
The number of rows, ${{m = 5}}$
Emf of each cell, ${{E = 1}}{{.5 V}}$
Internal resistance of each cell, ${{r = 1 \Omega }}$
Electric current is defined as the rate of flow of charge through a conductor in any cross sectional area in a definite direction. SI unit of electric current is ampere represented by A.
Emf is defined as the maximum potential difference between the terminal of the cell when no current is drawn from the cell or the circuit is open. SI unit of emf is voltage represented by V.
Internal resistance is the resistance offered by the electrolyte of the cells to the flow of charge. SI unit of internal resistance is ohms represented by $\Omega $.
Formula for current in mix grouping of cells is given by
$\Rightarrow {{i = }}\dfrac{{{{nE}}}}{{{{R + }}\dfrac{{{{nr}}}}{{{m}}}}}...{{(i)}}$
Where total resistance ${{ = R + }}\dfrac{{{{nr}}}}{{{m}}}$
Now substituting the given values in formula (i), we get
$
\Rightarrow {{i = }}\dfrac{{{{10 \times 15}}}}{{{{20 + }}\dfrac{{{{10 \times 1}}}}{{{5}}}}} \\
\Rightarrow {{i = }}\dfrac{{{{55}}}}{{{{22}}}} \\
\therefore {{i = 0}}{{.68 A}} $
Note: When the cells are joined in a mix group, then to get the maximum current the load resistance must be equal to the internal resistance of the cell. The value of emf of the cells connected in parallel combination remains the same i.e. ${{{E}}_{{{eqv}}}}{{ = E}}$.
For example: If 2 cells are connected in parallel or 100 cells connected in parallel combination the value of equivalent emf remains the same in both the cases.
Recently Updated Pages
If the magnetizing field on a ferromagnetic material class 12 physics JEE_Main

A point charge is placed at the corner of a cube The class 12 physics JEE_Main

What changes occur if the monochromatic light used class 12 physics JEE_Main

The unit of specific conductance is A Ohm B Ohmmetre class 12 physics JEE_Main

Which lens is used in magnifying glass A Concave lens class 12 physics JEE_Main

Sir C V Raman won the Nobel Prize in which year A 1928 class 12 physics JEE_Main

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

Understanding the Electric Field of a Uniformly Charged Ring

Understanding Atomic Structure for Beginners

Electron Gain Enthalpy and Electron Affinity Explained

Derivation of Equation of Trajectory Explained for Students

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
CBSE Class 12 Physics Question Paper 2026: Download SET-wise PDF with Answer Key & Analysis

JEE Advanced Percentile vs Marks 2026: JEE Main Cutoff, AIR & IIT Admission Guide

JEE Advanced 2026 Notification Out with Exam Date, Registration (Extended), Syllabus and More

What Are Current and Potential Difference in Electricity?

Understanding Uniform Acceleration in Physics

JEE Advanced Weightage Chapter Wise 2026 for Physics, Chemistry, and Mathematics

