If \[\dfrac{{\left( {{a^{n + 1}} + {b^{n + 1}}} \right)}}{{\left( {{a^n} + {b^n}} \right)}}\] be the arithmetic mean of \[a\] and \[b\], then what is the value of \[n\]?
A. 1
B. \[ - 1\]
C. 0
D. None of these
Answer
300.9k+ views
Hint:First, calculate the arithmetic mean of \[a\] and \[b\]. Then equate the given value with the arithmetic mean. Solve the equation to reach the required answer.
Formula Used:
An arithmetic mean of the two numbers \[x\] and \[y\] is: \[\dfrac{{x + y}}{2}\]
\[a{}^m \times {a^n} = {a^{m + n}}\]
Complete step by step solution:
Given:
The arithmetic mean of \[a\] and \[b\] is \[\dfrac{{\left( {{a^{n + 1}} + {b^{n + 1}}} \right)}}{{\left( {{a^n} + {b^n}} \right)}}\].
Let’s calculate the arithmetic mean of \[a\] and \[b\].
\[A.M. = \dfrac{{a + b}}{2}\]
Now equate it with the given value.
We get,
\[\dfrac{{\left( {{a^{n + 1}} + {b^{n + 1}}} \right)}}{{\left( {{a^n} + {b^n}} \right)}} = \dfrac{{a + b}}{2}\]
Cross multiply.
\[2\left( {{a^{n + 1}} + {b^{n + 1}}} \right) = \left( {a + b} \right)\left( {{a^n} + {b^n}} \right)\]
Factor out the common terms.
\[2{a^{n + 1}} + 2{b^{n + 1}} = a \times {a^n} + a \times {b^n} + b \times {a^n} + b \times {b^n}\]
\[ \Rightarrow \]\[2{a^{n + 1}} + 2{b^{n + 1}} = {a^{n + 1}} + {b^{n + 1}} + a{b^n} + b{a^n}\]
Cancel out the common terms.
\[{a^{n + 1}} + {b^{n + 1}} = a{b^n} + b{a^n}\]
Now apply the exponent property \[a{}^m \times {a^n} = {a^{m + n}}\].
\[a{a^n} + b{b^n} = a{b^n} + b{a^n}\]
\[ \Rightarrow \]\[a{a^n} - b{a^n} = a{b^n} - b{b^n}\]
Simplify the above equation.
\[\left( {a - b} \right){a^n} = \left( {a - b} \right){b^n}\]
Cancel out the common terms from both sides.
\[{a^n} = {b^n}\]
\[ \Rightarrow \]\[\dfrac{{{a^n}}}{{{b^n}}} = 1\]
\[ \Rightarrow \]\[{\left( {\dfrac{a}{b}} \right)^n} = 1\]
\[ \Rightarrow \]\[{\left( {\dfrac{a}{b}} \right)^n} = {\left( {\dfrac{a}{b}} \right)^0}\] [ Zero exponent rule]
Since \[a\] and \[b\] are two different numbers.
So, this is possible only when \[n = 0\].
Hence the correct option is C.
Note: The arithmetic mean of numbers is the ratio of the sum of numbers to the total number of numbers. It is also called an average of the numbers.
Zero exponent rule: If the exponent of any number is 0, then the output is 1.
Formula Used:
An arithmetic mean of the two numbers \[x\] and \[y\] is: \[\dfrac{{x + y}}{2}\]
\[a{}^m \times {a^n} = {a^{m + n}}\]
Complete step by step solution:
Given:
The arithmetic mean of \[a\] and \[b\] is \[\dfrac{{\left( {{a^{n + 1}} + {b^{n + 1}}} \right)}}{{\left( {{a^n} + {b^n}} \right)}}\].
Let’s calculate the arithmetic mean of \[a\] and \[b\].
\[A.M. = \dfrac{{a + b}}{2}\]
Now equate it with the given value.
We get,
\[\dfrac{{\left( {{a^{n + 1}} + {b^{n + 1}}} \right)}}{{\left( {{a^n} + {b^n}} \right)}} = \dfrac{{a + b}}{2}\]
Cross multiply.
\[2\left( {{a^{n + 1}} + {b^{n + 1}}} \right) = \left( {a + b} \right)\left( {{a^n} + {b^n}} \right)\]
Factor out the common terms.
\[2{a^{n + 1}} + 2{b^{n + 1}} = a \times {a^n} + a \times {b^n} + b \times {a^n} + b \times {b^n}\]
\[ \Rightarrow \]\[2{a^{n + 1}} + 2{b^{n + 1}} = {a^{n + 1}} + {b^{n + 1}} + a{b^n} + b{a^n}\]
Cancel out the common terms.
\[{a^{n + 1}} + {b^{n + 1}} = a{b^n} + b{a^n}\]
Now apply the exponent property \[a{}^m \times {a^n} = {a^{m + n}}\].
\[a{a^n} + b{b^n} = a{b^n} + b{a^n}\]
\[ \Rightarrow \]\[a{a^n} - b{a^n} = a{b^n} - b{b^n}\]
Simplify the above equation.
\[\left( {a - b} \right){a^n} = \left( {a - b} \right){b^n}\]
Cancel out the common terms from both sides.
\[{a^n} = {b^n}\]
\[ \Rightarrow \]\[\dfrac{{{a^n}}}{{{b^n}}} = 1\]
\[ \Rightarrow \]\[{\left( {\dfrac{a}{b}} \right)^n} = 1\]
\[ \Rightarrow \]\[{\left( {\dfrac{a}{b}} \right)^n} = {\left( {\dfrac{a}{b}} \right)^0}\] [ Zero exponent rule]
Since \[a\] and \[b\] are two different numbers.
So, this is possible only when \[n = 0\].
Hence the correct option is C.
Note: The arithmetic mean of numbers is the ratio of the sum of numbers to the total number of numbers. It is also called an average of the numbers.
Zero exponent rule: If the exponent of any number is 0, then the output is 1.
Recently Updated Pages
If a parabola whose length of latus rectum is 4a touches class 11 maths JEE_Main

Find the cubic polynomial whose zeroes are 3 5 and class 11 maths JEE_Main

During the sale colour pencils were being sold in -class-11-maths-JEE_Main

A man on the top of a vertical observation tower o-class-11-maths-JEE_Main

In a class of 60 students 25 students play cricket class 11 maths JEE_Main

A regular polygon has 20 sides How many triangles can class 11 maths JEE_Main

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

Understanding the Electric Field of a Uniformly Charged Ring

Electron Gain Enthalpy and Electron Affinity Explained

Derivation of Equation of Trajectory Explained for Students

Understanding Atomic Structure for Beginners

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
NCERT Solutions For Class 11 Maths Chapter 6 Permutations And Combinations - 2026-27 Free PDF Download (Login Required)

NCERT Solutions For Class 11 Maths Chapter 9 Straight Lines - 2026-27 Free PDF Download (Sign-in Required)

JEE Advanced Percentile vs Marks 2026: JEE Main Cutoff, AIR & IIT Admission Guide

NCERT Solutions For Class 11 Maths Chapter 8 Sequences And Series - 2026-27 Free PDF Download (Login Required)

NCERT Solutions For Class 11 Maths Chapter 4 Complex Numbers And Quadratic Equations - 2026-27 Free PDF Download (Login Required)

Hybridisation in Chemistry – Concept, Types & Applications

