If $A=\left( \begin{matrix}
0 & 1 \\
1 & 0 \\
\end{matrix} \right)$ then ${{A}^{4}}$ is equal to
A . $\left( \begin{matrix}
1 & 0 \\
0 & 1 \\
\end{matrix} \right)$
B. $\left( \begin{matrix}
1 & 1 \\
0 & 0 \\
\end{matrix} \right)$
C. $\left( \begin{matrix}
0 & 0 \\
1 & 1 \\
\end{matrix} \right)$
D. $\left( \begin{matrix}
0 & 1 \\
1 & 0 \\
\end{matrix} \right)$
Answer
298.8k+ views
Hint: In this question, we have given a matric A and we have to find out the value of ${{A}^{4}}$. We know ${{A}^{4}}$ is also written as ${{A}^{4}}={{A}^{2}}\times {{A}^{2}}$. So we find the square matrix of A. After finding out the square matrix, we find out the ${{A}^{4}}$ and choose the correct option.
Complete step by step Solution:
We have given a matrix $A=\left( \begin{matrix}
0 & 1 \\
1 & 0 \\
\end{matrix} \right)$
Here matrix A is a $2\times 2$ matrix with 2 rows and 2 columns.
We have to find the value of ${{A}^{4}}$
We know ${{A}^{4}}={{A}^{2}}\times {{A}^{2}}$
To find ${{A}^{4}}$, first, we find the ${{A}^{2}}$.
We know ${{A}^{2}}=A\times A$
${{A}^{2}}=\left( \begin{matrix}
0 & 1 \\
1 & 0 \\
\end{matrix} \right)\left( \begin{matrix}
0 & 1 \\
1 & 0 \\
\end{matrix} \right)$
Now, we open the brackets and multiply the terms, we get
${{A}^{2}}=\left( \begin{matrix}
0+1 & 0+0 \\
0+0 & 1+0 \\
\end{matrix} \right)$
Adding the terms and simplifying them, we get
${{A}^{2}}=\left( \begin{matrix}
1 & 0 \\
0 & 1 \\
\end{matrix} \right)$
Now we find out the value of ${{A}^{4}}$.
${{A}^{4}}$= $\left( \begin{matrix}
1 & 0 \\
0 & 1 \\
\end{matrix} \right)\times \left( \begin{matrix}
1 & 0 \\
0 & 1 \\
\end{matrix} \right)$
Again we open the brackets and multiply the terms, we get
${{A}^{4}}$= $\left( \begin{matrix}
0+1 & 0+0 \\
0+0 & 1+0 \\
\end{matrix} \right)$
Now we add the terms and get the new matrix which is
Then ${{A}^{4}}$= $\left( \begin{matrix}
1 & 0 \\
0 & 1 \\
\end{matrix} \right)$
Hence the value of ${{A}^{4}}$= $\left( \begin{matrix}
1 & 0 \\
0 & 1 \\
\end{matrix} \right)$
Therefore, the correct option is (A).
Note: Students must have the knowledge of solving the question related to matrix multiplication. By multiplication property, two matrices can be multiplied only when the columns of the first row are equal to the rows of the second matrix. Elements of a row of the first matrix will get multiplied with all the elements of the column of the second matrix and we will add them to get a new matrix. Students must do a lot of practice multiplying the two matrices otherwise they get confused while multiplying and choose the incorrect option.
Complete step by step Solution:
We have given a matrix $A=\left( \begin{matrix}
0 & 1 \\
1 & 0 \\
\end{matrix} \right)$
Here matrix A is a $2\times 2$ matrix with 2 rows and 2 columns.
We have to find the value of ${{A}^{4}}$
We know ${{A}^{4}}={{A}^{2}}\times {{A}^{2}}$
To find ${{A}^{4}}$, first, we find the ${{A}^{2}}$.
We know ${{A}^{2}}=A\times A$
${{A}^{2}}=\left( \begin{matrix}
0 & 1 \\
1 & 0 \\
\end{matrix} \right)\left( \begin{matrix}
0 & 1 \\
1 & 0 \\
\end{matrix} \right)$
Now, we open the brackets and multiply the terms, we get
${{A}^{2}}=\left( \begin{matrix}
0+1 & 0+0 \\
0+0 & 1+0 \\
\end{matrix} \right)$
Adding the terms and simplifying them, we get
${{A}^{2}}=\left( \begin{matrix}
1 & 0 \\
0 & 1 \\
\end{matrix} \right)$
Now we find out the value of ${{A}^{4}}$.
${{A}^{4}}$= $\left( \begin{matrix}
1 & 0 \\
0 & 1 \\
\end{matrix} \right)\times \left( \begin{matrix}
1 & 0 \\
0 & 1 \\
\end{matrix} \right)$
Again we open the brackets and multiply the terms, we get
${{A}^{4}}$= $\left( \begin{matrix}
0+1 & 0+0 \\
0+0 & 1+0 \\
\end{matrix} \right)$
Now we add the terms and get the new matrix which is
Then ${{A}^{4}}$= $\left( \begin{matrix}
1 & 0 \\
0 & 1 \\
\end{matrix} \right)$
Hence the value of ${{A}^{4}}$= $\left( \begin{matrix}
1 & 0 \\
0 & 1 \\
\end{matrix} \right)$
Therefore, the correct option is (A).
Note: Students must have the knowledge of solving the question related to matrix multiplication. By multiplication property, two matrices can be multiplied only when the columns of the first row are equal to the rows of the second matrix. Elements of a row of the first matrix will get multiplied with all the elements of the column of the second matrix and we will add them to get a new matrix. Students must do a lot of practice multiplying the two matrices otherwise they get confused while multiplying and choose the incorrect option.
Recently Updated Pages
Letfx be a polynomial with positive degree satisfy-class-12-maths-JEE_Main

Evaluate the definite integral given as intlimits13left class 12 maths JEE_Main

The sum of squares of two parts of a number 100 is-class-12-maths-JEE_Main

Geometry of Complex Numbers Explained

JEE Main 2023 (February 1st Shift 2) Physics Question Paper with Answer Key

JEE Main 2023 (February 1st Shift 1) Maths Question Paper with Answer Key

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

Understanding the Electric Field of a Uniformly Charged Ring

Understanding Atomic Structure for Beginners

Electron Gain Enthalpy and Electron Affinity Explained

Derivation of Equation of Trajectory Explained for Students

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Percentile vs Marks 2026: JEE Main Cutoff, AIR & IIT Admission Guide

JEE Advanced 2026 Notification Out with Exam Date, Registration (Extended), Syllabus and More

What Are Current and Potential Difference in Electricity?

Hybridisation in Chemistry – Concept, Types & Applications

Understanding Geostationary and Geosynchronous Satellites

Isoelectronic Species: Definition, Examples & Importance

