Four identical rods of the same material are joined at ends so as to form a square. If the temperature difference at the ends of a diagonal is ${{100}^{\circ }}C$, then the temperature difference across the ends of another diagonal will be
A. ${{0}^{\circ }}C$
B. ${{25}^{\circ }}C$
C. ${{50}^{\circ }}C$
D. ${{100}^{\circ }}C$
Answer
302.7k+ views
Hint: We have given four identical rods which are joined to form a square and we have to find the temperature difference across the diagonals. As we know heat will be transferred due to temperature difference and heat flows from higher temperature to lower temperature. So by using the difference in the temperature , we are able to find the temperature difference.
Complete step by step solution:
Let the four identical rods be A,B,C and D which have AC and BD as a diagonal point. We are asked to find the temperature difference between points B and D, which is ${{T}_{B}}-{{T}_{D}}$.
Consider the temperature at A = ${{T}^{\circ }}C$
Therefore, temperature at C = $t+{{100}^{\circ }}C$
As heat is conducted from A to C via B or D. B and D lie midway along with the passing of heat conduction through ABC and ADC respectively.
Hence temperature of B = \[\dfrac{t+(t+100)}{2}\] = $t+{{50}^{\circ }}C$
Similarly temperature of D = \[\dfrac{t+(t+100)}{2}\] = $t+{{50}^{\circ }}C$
So the temperature difference across the ends of another diagonal will be ${{0}^{\circ }}C$.
Hence, option A is the correct answer.
Note: By conduction, we mean the transfer of energy when one of the parts of an object is heated and it gets excited and transfers energy to its nearest particle, which further transmits the energy and with this process, heat energy gets transferred from one end to another.
Complete step by step solution:
Let the four identical rods be A,B,C and D which have AC and BD as a diagonal point. We are asked to find the temperature difference between points B and D, which is ${{T}_{B}}-{{T}_{D}}$.
Consider the temperature at A = ${{T}^{\circ }}C$
Therefore, temperature at C = $t+{{100}^{\circ }}C$
As heat is conducted from A to C via B or D. B and D lie midway along with the passing of heat conduction through ABC and ADC respectively.
Hence temperature of B = \[\dfrac{t+(t+100)}{2}\] = $t+{{50}^{\circ }}C$
Similarly temperature of D = \[\dfrac{t+(t+100)}{2}\] = $t+{{50}^{\circ }}C$
So the temperature difference across the ends of another diagonal will be ${{0}^{\circ }}C$.
Hence, option A is the correct answer.
Note: By conduction, we mean the transfer of energy when one of the parts of an object is heated and it gets excited and transfers energy to its nearest particle, which further transmits the energy and with this process, heat energy gets transferred from one end to another.
Recently Updated Pages
Four persons A B C and D initially at the corners of class 11 physics JEE_Main

What is the difference between Conduction and conv class 11 physics JEE_Main

Moment of inertia of solid sphere about its diameter class 11 physics JEE_Main

If a piece of ice floating on the surface of water class 11 physics JEE_Main

At what temperature speed of sound in air will be doubled class 11 physics JEE_Main

A closed organ pipe and an open organ pipe are tuned class 11 physics JEE_Main

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

Understanding the Electric Field of a Uniformly Charged Ring

Derivation of Equation of Trajectory Explained for Students

Understanding Atomic Structure for Beginners

Understanding Uniform Acceleration in Physics

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
CBSE Notes Class 11 Physics Chapter 1 - Units And Measurements - 2026-27 PDF Download (Login Required)

NCERT Solutions For Class 11 Physics Chapter 1 Units And Measurements - 2026-27 Free PDF Download (Login Required)

NCERT Solutions For Class 11 Physics Chapter 2 Motion In A Straight Line - 2026-27 Free PDF Download (Login Required)

Important Questions For Class 11 Physics Chapter 1 Units and Measurement - 2026-27 Free PDF Download (Sign-in Required)

CBSE Notes Class 11 Physics Chapter 2 - Motion in a Straight Line - 2026-27 PDF Download (Login Required)

NCERT Solutions For Class 11 Physics Chapter 3 Motion In A Plane - 2026-27 Free PDF Download (Sign-in Required)

