Among the following which one does not act as an intermediate in Hofmann rearrangement?
A. RNCO
B. RCON
C. RCONHBr
D. RNC

Hint: Hofmann rearrangement also called Hofmann degradation is a rearrangement reaction of primary amides with bromine and aqueous or alcoholic potassium hydroxide to give primary amines. Overall, in the end, the carbonyl group get removed from the product.

Complete Step by Step Solution:
A lot of intermediates can be found in this reaction because of a lot of steps present in the reaction. After step-by-step solving the reaction, all three above intermediates formed in the reaction except option D i.e., RNC. The reaction mechanism is shown below:

Image:Mechanism of Hoffmann rearrangement

At first hydroxyl ion of the base \[KOH\]accepts \[{H^ + }\]from \[N\]of amide functional group to form an \[RCON\]intermediate, then \[B{r^ + }\]of \[B{r_2}\]attacks on \[{N^ - }\]of intermediate to form\[RCONHBr\]. Then again, the base accepts another \[{H^ + }\]of the amide functional group. Now, the \[R\]group migrates to Nitrogen and \[Br\]ion leaves as it is a leaving group and gives an \[RNCO\]intermediate. After that, proton and hydroxyl ions of water get added to the intermediate and give carbamic acid which gives amine as a final product with the loss of carbon dioxide gas.

So, the option D is correct.

Additional Information:The carbon dioxide gas released in the last step is the driving force of the reaction as this increases the entropy of the reaction, due to which the reaction becomes spontaneous.

Note: Hofmann rearrangement is an organic reaction of primary amides and not the Hofmann elimination reaction. Hofmann elimination is the elimination reaction to form an alkene product.