A student obtained a clear image of window grills on the screen. But the teacher told him to get the image of a tree far away, instead of the window. To get a clear image the lens must be:
A) Moved towards the screen
B) Moved away from the screen
C) Moved very close to the screen
D) None of these.
Answer
301.2k+ views
Hint: from the above question it is clear that the distance of the tree from the lens is greater than the distance of the window grills. Now a lens is kept between the window grills and a screen and the student getting a clear image of the grills. The lens should be converging as the tree is far away from the grills. In the converging lens, the nearer the object the more distance the image from the lens. Therefore for the faraway tree, the image will be near the lens.
Complete solution:
Step 1: First let us understand how a converging lens forms the image and how the position of the object affects the position of the image. Consider the following diagram.
In the ray diagram window grills, AB is closer to the lens in comparison to the tree CD. Since the student is getting a clear image of the window grill therefore the screen kept by the student will be at the same distance as the distance of the image of the window grills A’B’.
Step 2: From the above diagram it is also clear that when the student was getting a clear image of the window grills then the image of the tree which is far away from the grills was being formed between the screen and the lens. The screen is fixed. If we can only move the lens then it is pretty clear that the lens should be moved towards the screen to get a clear image of the tree. Then only the image C’D’ can be found clearly on the screen.
Hence the correct option is Option A.
Note: The lens cannot be moved away from the screen if we want a clear image of the tree. Because the distance of the image from the lens of an object depends on the distance of the object from the lens. In the case of the converging lens the far the object is kept nearer the image is formed. If we took the lens away from the screen then the image of the tree will go away from the screen.
Complete solution:
Step 1: First let us understand how a converging lens forms the image and how the position of the object affects the position of the image. Consider the following diagram.
In the ray diagram window grills, AB is closer to the lens in comparison to the tree CD. Since the student is getting a clear image of the window grill therefore the screen kept by the student will be at the same distance as the distance of the image of the window grills A’B’.Step 2: From the above diagram it is also clear that when the student was getting a clear image of the window grills then the image of the tree which is far away from the grills was being formed between the screen and the lens. The screen is fixed. If we can only move the lens then it is pretty clear that the lens should be moved towards the screen to get a clear image of the tree. Then only the image C’D’ can be found clearly on the screen.
Hence the correct option is Option A.
Note: The lens cannot be moved away from the screen if we want a clear image of the tree. Because the distance of the image from the lens of an object depends on the distance of the object from the lens. In the case of the converging lens the far the object is kept nearer the image is formed. If we took the lens away from the screen then the image of the tree will go away from the screen.
Recently Updated Pages
If the magnetizing field on a ferromagnetic material class 12 physics JEE_Main

A point charge is placed at the corner of a cube The class 12 physics JEE_Main

What changes occur if the monochromatic light used class 12 physics JEE_Main

The unit of specific conductance is A Ohm B Ohmmetre class 12 physics JEE_Main

Which lens is used in magnifying glass A Concave lens class 12 physics JEE_Main

Sir C V Raman won the Nobel Prize in which year A 1928 class 12 physics JEE_Main

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

Understanding the Electric Field of a Uniformly Charged Ring

Electron Gain Enthalpy and Electron Affinity Explained

Derivation of Equation of Trajectory Explained for Students

Understanding Atomic Structure for Beginners

Understanding Uniform Acceleration in Physics

Other Pages
CBSE Class 12 Physics Question Paper 2026: Download SET-wise PDF with Answer Key & Analysis

JEE Advanced Percentile vs Marks 2026: JEE Main Cutoff, AIR & IIT Admission Guide

How to Convert a Galvanometer into an Ammeter or Voltmeter

Hybridisation in Chemistry – Concept, Types & Applications

What Are Elastic Collisions in One Dimension?

Effective Nuclear Charge for JEE

